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n200080 [17]
3 years ago
7

If I give my teacher chocolate, then she will give me less homework because she will be happier

Chemistry
1 answer:
Softa [21]3 years ago
6 0
Good idea!maybe I should try that
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How sensitive to changes in water temperature are coral reefs? To find out, measure the growth of corals in aquariums where the
Dimas [21]

Answers:

(a) The explanatory variable is the change in the temperature .

The response variable is the coral survivance.

(b) The explanatory variable is quantitative.

The response variable is categorical.

Explanation:

A quantitative variable is those that can take a range of values. In this case, the temperature may vary across a range of values associated with the survival of coral reefs.  

A categorical (also known as qualitative) variable is characterized to present finite states. In this case, the coral reefs can survive or not depending on their responses to changes in the temperature.

7 0
3 years ago
A 7.0 L sample of gas begins at 2.5 atm and 320. K. What is the new pressure if the temperature is changed to 273 K and the volu
enyata [817]

Answer:

2.1 atm

Explanation:

We are given the following variables to work with:

Initial pressure (P1): 2.5 atm

Initial temperature (T1): 320 K

Final temperature (T2): 273 K

Constant volume: 7.0 L

We are asked to find the final pressure (P2). Since volume is constant, we want to choose a gas law equation that relates initial pressure and temperature to final pressure and temperature. Gay-Lussac's law does this:

\frac{P_{1}}{T_1} =\frac{P_{2}}{T_2} \\

We can rearrange the law algebraically to solve for P_{2}.

{P_{2}} =\frac{(T_2)(P_{1} )}{T_1} \\

Substitute your known variables and solve:

P_2 = \frac{273K(2.5atm)}{320K}  = 2.1 atm

4 0
3 years ago
if the initial concentration of acetic acid is .200 M and the equilibrium concentration of H3O+ is .0019 M, calculate Ka for ace
Blizzard [7]

Answer:

The first one

Explanation:

- K must be calculated with the concentrations AT equilibrium, not initial concentrations.

4 0
3 years ago
Students were asked to identify the location of elements in the
Naddika [18.5K]

Answer:амьсгал боогдов гэж найдаж байна

Explanation:

4 0
3 years ago
Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu
ad-work [718]

Initial volume of the balloon = V_{1}= 348 mL

Initial temperature of the balloon T_{1} = 25.0^{0}C + 273 = 298 K

Final volume of the balloon V_{2} = 322 mL

Final temperature of the balloon = T_{2} = ?

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

On plugging in the values,

\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }

T_{2} =276 K

Therefore, the temperature of the freezer is 276 K

5 0
3 years ago
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