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SSSSS [86.1K]
3 years ago
12

Given the vertex and another point, write the equation in vertex form: vertex (2, -5) point (3, -2)

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

y = 3(x - 2)² - 5

Step-by-step explanation:

Let the equation of the parabola is,

y = a(x - h)² + k

Here, (h, k) is the vertex of the given parabola.

Since, vertex of the parabola is (2, -5)

Equation of the parabola will be,

y = a(x - 2)²- 5

Since, parabola passes through a point (3, -2),

-2 = a(3 - 2)²- 5

-2 + 5 = a(1)

a = 3

Therefore, equation of the parabola will be,

y = 3(x - 2)²- 5

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For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
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Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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What is the average rate of change for this exponential function for the interval from x = 2 to x = 4?
Hunter-Best [27]

Answer:

The average rate of change over the interval is 120

Step-by-step explanation:

For a function f(x) the average rate of change over an interval [a,b] is given as;

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in this case, a is 2 and b is 4

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Substituting these values in the equation for rate of change, we have;

(256-16)/(4-2) = 240/2 = 120

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If the point A is located at ( –5, – 3) and A’ is the image of A after being rotated about the origin by 270° (counter clockwise
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A'(- 3, 5 )

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Which polynomial is in standard form
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