y = 0.6x - 3.2
The general form of the desired equation is
y = mx + b
where
m = slope of the line
b = y intercept of the line
If two lines are parallel, their slopes will be the same, Since the slope of the
given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line.
So our equation becomes:
y = 0.6x + b
Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So
y = 0.6x + b
-5 = 0.6(-3) + b
-5 = -1.8 + b
-3.2 = b
So the desired equation is now
y = 0.6x - 3.2
Answer:
$25000
Step-by-step explanation:
If the salvage value is 20% of the cost, then 80% of the cost will be depreciated over 10 years. Over the 5 years from Jan 1 20X1 to Dec 31 20X5, the $10,000 accumulated depreciation represents 5/10 of that 80%, or 40% of the initial cost.
$10,000 = 0.40 × cost
$10,000/0.40 = cost = $25,000
The acquisition cost of the equipment was $25,000.
I believe the answer is 4x + 8. you multiply 4 by x which makes 4x. Than you multiply 4 by 2, making 8.
It should be this y=1/2x+3
1) isolate k: 3(-4)>-k
2) combine like terms: -12>-k
3) get rid of the negative sign (NOTE WHEN YOU DIVIDE BY A NEGATIVE IN AN INEQUALITY YOU MUST FLIP THE SIGN): 12
ANSWER: 12
