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bogdanovich [222]
3 years ago
8

Help me pleaseeeeeeeee

Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0
Because it’s an equalacteral it should be 60
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Solve systems of three variable equations - how to do :(​
krek1111 [17]

a= 6-2b-3c

then put that equation inside the first one and then the second one

you get -6*(6-2b-3c)+2b-3c=23

and 5*(6-2b-3c)+4b-3c=-12

14b-15c=59

14b-18c=18/*(-1)

--------------------

3b=41

7 0
3 years ago
What is the answer to 4|x-1|=12
STatiana [176]

Answer:

(4,0) and (- 2,0): Answer

Step-by-step explanation:

Absolute value questions have two essential steps.

1. Solve the equation as it is written.

2. Solve it changing the sign of the right hand side. I will include a graph to confirm my answer

4*abs(x - 1) = 12             Divide by 4

  • abs(x - 1) = 12/4            
  • abs(x - 1) = 3                  Equate this to 3
  • x - 1 = 3                          Add 1 to both sides
  • x - 1 + 1 = 3 + 1               Combine
  • x = 4

4*abs(x - 1) = - 12         Divide by 4

  • abs(x - 1) = - 12/4
  • abs(x - 1) = - 3
  • x - 1 = - 3                       Add 1 to both sides
  • x - 1 + 1 = -3 + 1
  • x = - 2

So this has 2 answers

(4,0) and (- 2,0)

5 0
3 years ago
Write as a product: ax^2+ay^2–bx^2–by^2+b–a
Vesna [10]

Answer:

\large\boxed{ax^2+ay^2-bx^2-by^2+b-a=(a-b)(x^2+y^2-1)}

Step-by-step explanation:

ax^2+ay^2-bx^2-by^2+b-a\\\\=(ax^2-bx^2)+(ay^2-by^2)+(b-a)\qquad\text{use the distributive property}\\\\=x^2(a-b)+y^2(a-b)-1(a-b)\\\\=(a-b)(x^2+y^2-1)

4 0
3 years ago
Mark tossed six balls
Ivanshal [37]
Six balls fell back down
8 0
3 years ago
Read 2 more answers
I need help with this please
Harlamova29_29 [7]
-12y+14-9y=14
-21y=0
y=0, x=7
3 0
3 years ago
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