Sqrt of 125
10^2 +b^2= 15^2
100 +b^2=225
B^2=125
No perfect square for 125 so leave it in radical form
-(3/4) (12)+1 = -9+1=. -8
Answer:
80
Step-by-step explanation:
10+4+2+4=20 and 20×4 numbers=80
Table:
x y
5 2
6 5
7 8
8 11
<span>Part A: Do the data in this table represent a function? Justify your answer.
Yes, they do. Because for input set is related with a wll defined output, unambiguosly.
Part B: Compare the data in the table with the relation f(x) = 2x + 13. Which relation has a greater value when x = 7?
The relation f(x) = 2x + 13 results in these points
x f(x)
5 23
6 25
7 27
8 29
The relation f(x) = 2x + 13 has a greater value than the relation of the first table when x =7
Part C: Using the relation in Part B, what is the value of x if f(x) = 75?
</span>f(x) = 2x + 13 = 75 => x = [75 - 13] / 2 = 31
if f(x) = 75, x = 31
