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stira [4]
2 years ago
14

PLS HELP MEEEEE And please SHOW YOUR WORK

Mathematics
1 answer:
vfiekz [6]2 years ago
4 0

- 13.8 =  \frac{u}{5}  - 1.3

- 13.8 + 1.3 =  \frac{u}{5}

- 12.5 =  \frac{u}{5}

- 12.5 \times 5 = u

- 62.5 = u

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Find the volume of the prism.
Rudik [331]

Answer:

216 cubic meters

Step-by-step explanation:

to find the volume of any prism the equation is bh or base times height

the base is a triangle so you find the triangles area and multiply it by the height

8 * 6 * 1/2 = 24

24 * 9 = 216

216 cubic meters

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2 years ago
Which of the following could be the interpretation of the distance vs time graph shown?
JulijaS [17]

Answer:

3

Step-by-step explanation:

If you notice the y is the change in distance, so #3 has the best explanation.

5 0
3 years ago
Write the slope intercept form through: (5,1) and(2, -2)
victus00 [196]

We see that the slope of this line is \frac{-2-1}{2-5}=1, so we plug this and the point (5,1) into the point-slope form y-y_1=m(x-x_1) (note that there's nothing special about the point I picked; you can choose any point on the line):

y-1=x-5. This rearranges to the slope-intercept form \boxed{y=x-4}.

3 0
3 years ago
One day the temperature was 72.8 degrees F. The temperature dropped to -2.7 degrees. difference, please
djverab [1.8K]

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the difference is 75.5

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
50 PTS ANSWER ALL <3333333
11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

{h}^{2}  = 36+ 64

{h}^{2}  = 100

h =  \sqrt{100}

h = 10cm

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

{l}^{2}  =  {55}^{2}  -  {33}^{2}

{l}^{2}  = 1936

l =  \sqrt{1936}

l = 44cm

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

d=\sqrt{25}

d = 5

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

d=\sqrt{( - 5)^2+( - 5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

Answer: D

8 0
2 years ago
Read 2 more answers
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