Ask question

Ask question

All categories

3 years ago

12

What is -3-4b= 25-8b

1 answer:

sammy [17]3 years ago

6 0

Answer:

b=7

Step-by-step explanation:

-3-4b= 25-8b Add 3 to both sides

-4b=28-8b Add 8b to both sides

4b=28 Divide 4 to both sides

b=7

You might be interested in

Eight less than four times a number is less than 56. What are the possible values of that number?

Damm [24]

For this case we can algebraically rewrite the expression given as:

$8-4x$

Where:

x: Represents the unknown number

Subtracting 8 from both sides of the inequality we have:

$-4x$

Dividing between 4 on both sides of the inequality:

$-x$

We multiply by -1 on both sides taking into account that the sense of inequality changes:

$x> -12$

ANswer:

$x> -12$

4 0

4 years ago

Read 2 more answers

What is the area of 1 times 6/7?

Rzqust [24]

It's 6/7 because 1 times anything like 1x10 =10 so it 6/7

6 0

3 years ago

Read 2 more answers

consider the following simplified algebraic expression 10x²y+6x²-7y²-6 which could be the original expression

slava [35]

Answer:

You technically can't do anything with it since it the algebraic expression doesn't factor.

Step-by-step explanation:

3 0

3 years ago

A sandwich shop sells a foot-long grinder for $8 and a calzone for $6. Which equation shows the relationship between the amount

makvit [3.9K]

Answer:

B. 6x + 8y = z , x represents the calzones sold; y represents grinders sold; z represents total sales.

7 0

2 years ago

What is the rate of change for f(x)=-2cos4x-3 on the interval from x=0 to x=pi over 4

Anestetic [448]

Answer:

$\frac{16}{\pi}$

Step-by-step explanation:

The average rate of a function $f$ on interval $x=a$ to $x=b$ is:

$\frac{f(b)-f(a)}{b-a}$ .

$a=0$ and $b=\frac{\pi}{4}$ here for this problem where $f(x)=-2\cos(4x)-3$ .

So we will need to evaluate $f$ for $x=0 \text{ and } b=\frac{\pi}{4}$ .

To find $f(0)$ we will replace $x$ in $f(x)=-2\cos(4x)-3$ with $0$ :

$f(0)=-2\cos(4(0))-3$

$f(0)=-2\cos(0)-3$

$f(0)=-2(1)-3$

$f(0)=-2-3$

$f(0)=-5$

To find $f(\frac{\pi}{4})$ we will replace $x$ in $f(x)=-2\cos(4x)-3$ with $\frac{\pi}{4}$ :

$f(\frac{\pi}{4})=-2\cos(4(\frac{\pi}{4}))-3$

$f(\frac{\pi}{4})=-2\cos(\pi)-3$

$f(\frac{\pi}{4})=-2(-1)-3$

$f(\frac{\pi}{4})=2-3$

$f(\frac{\pi}{4})=-1$

So now we need to compute the change in $f$ over the change in $x$ :

$\frac{-1-(-5)}{\frac{\pi}{4}-0}$

$\frac{-1+5}{\frac{\pi}{4}}$

Dividing by $\frac{\pi}{4}$ is the same as multiplying by $\frac{4}{\pi}$ :

$(-1+5)\cdot \frac{4}{\pi}$

$4 \cdot \frac{4}{\pi}$

$\frac{16}{\pi}$

8 0

3 years ago