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Maurinko [17]
3 years ago
11

Pls help me asap for brainlest

Mathematics
2 answers:
Leno4ka [110]3 years ago
5 0

Answer: The third one, I think.

( I'm sowwie if I'm wrong but I hope this was helpful) >;D

PIT_PIT [208]3 years ago
4 0

Answer:

Option 3

Step-by-step explanation:

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If you score 30 points in 5 games, how many points do you score per game?
Yuki888 [10]

Answer:

You scored 6 points per game

Step-by-step explanation:

30÷5=6

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2 years ago
What solid figure has 7 vertices?
Natalija [7]
Pyramids or prisms can have 7 or more vertices.
3 0
3 years ago
Valerie ran Three and one-fourth laps yesterday, and her coach wants her to run Two and one-half times that many laps today. How
Maru [420]

Answer:

13/4 * 5/2

Step-by-step explanation:

In the question, it says that her coach wants her to run 2 1/2 TIMES the original 3/4 she had ran. Therefore, you would want to make the fractions into improper fractions, and then multiply, which is how you would get 13/4 * 5/2.

6 0
3 years ago
What is 6/2(1+2)? Correct answers only please!!
kherson [118]

Answer:

your answer is 9

hope this helps xx

8 0
3 years ago
Read 2 more answers
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
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