if a > 0, b>0, show that f(x)= a(1-e^-bx) is everywhere increasing and everywhere concave down.
1 answer:
You might be interested in
we have
we know that
<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms
p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.
So
in this problem
the constant term is equal to
and the first monomial is equal to -----> coefficient is
So
possible values of p are
possible values of q are
therefore
<u>the answer is</u>
The all potential rational roots of f(x) are
(+/-),(+/-)
,(+/-)
,(+/-)
,(+/-)
,(+/-)
Answer:
See explanation
Step-by-step explanation:
Given
According to the order of the vertices,
- side AB in triangle ABC (the first and the second vertices) is congruent to side AD in triangle ADC (the first and the second vertices);
- side BC in triangle ABC (the second and the third vertices) is congruent to side DC in triangle ADC (the second and the third vertices);
- side AC in triangle ABC (the first and the third vertices) is congruent to side AC in triangle ADC (the first and the third vertices);
- angle BAC in triangle ABC is congruent to angle DAC in triangle ADC (the first vertex in each triangle is in the middle when naming the angles);
- angle ABC in triangle ABC is congruent to angle ADC in triangle ADC (the second vertex in each triangle is in the middle when naming the angles);
- angle BCA in triangle ABC is congruent to angle DCA in triangle ADC (the third vertex in each triangle is in the middle when naming the angles);