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Tom [10]
3 years ago
15

if a > 0, b>0, show that f(x)= a(1-e^-bx) is everywhere increasing and everywhere concave down.

Mathematics
1 answer:
faltersainse [42]3 years ago
4 0
If a > 0, b>0, show that f(x)= a(1-e^-bx)
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F(x)=5500(1.65) <br> at what percent are the bacteria growing each hour
kodGreya [7K]
So exponenetial growth or decay

it goes like this
f(t)=P(1+r)^t
r=rate of decay or grouth
if r>0 then it is grouth by r
if r<0 then it is decay
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P=initial amount
so
given
f(x)=5500(1.65)^t
f(x)=5500(1+0.65)^t
0.65>0 so it is growing by 65%
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ANEK [815]

Step-by-step explanation:

\frac{3}{10 }  = .3

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How many lines of symmetry does the shape below appear to have?
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Step-by-step explanation:

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6/5 × 25/24
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