hookes law gives the equation F=kx where F is the elastic force and k is the constant and x or small e is extension if we draw a graph you'll see that the graph increases by the same ratio every single time hence giving a straight line show that they are F and x are propotional to a certain limit
Answer:
test? is it? if it is i can't tell you
Step-by-step explanation:
Answer:
<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>
Step-by-step explanation:





Answer:
72.175
Step-by-step explanation:
The first step is subtract 94.68 by 49.67 which would be 45.01
The next step would be to use 45.01 and divide by two
The last step would be subtract 94.68 by 22.505 and you would get 72.175
Therefore your answer would be 72.175
Answer:If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is 1/6.
If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is 3/6 = 1/2
Step-by-step explanation:For example, when a die is rolled, the possible outcomes are 1, 2, 3, 4, 5, and 6. In mathematical language, an event is a set of outcomes, which describe what outcomes correspond to the "event" happening. For instance, "rolling an even number" is an event that corresponds to the set of outcomes {2, 4, 6}. The probability of an event, like rolling an even number, is the number of outcomes that constitute the event divided by the total number of possible outcomes. We call the outcomes in an event its "favorable outcomes".