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Misha Larkins [42]

3 years ago

7

The axis of symmetry for a function in the form f(x)=x2+4x-5 is x=-2

1 answer:

Valentin [98]3 years ago

6 0

Answer:

error siya bessssss

error siya

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8/9 + (−5/ 6) divided by 1/6

rusak2 [61]

Answer:

-4 1/9

Step-by-step explanation:

5 0

3 years ago

Write the expression in exponential form. <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B10%7D%20" id="TexFormula1" title="

adoni [48]

<h3>Answer: 10^(1/2)</h3>

When we use an exponent of 1/2, it is the same as a square root. The more general rule is

$\sqrt{x} = x^{1/2}$

In this case, we plug in x = 10.

The use of a fractional exponent is handy when you want to deal with things like cube roots on a calculator. This is because

$\sqrt[3]{x} = x^{1/3}$

Many calculators don't have a button labeled $\sqrt[3]{}$ but they have the button $x^y$ to allow fractional exponents.

3 0

3 years ago

Neeeeeed helllllpppp

tester [92]

Your answer is:
u = x + 3

4 0

3 years ago

Read 2 more answers

Please help me fill in the blanks :) marking most Brainly

Gala2k [10]

Answer:

For the part that contains organic matter your answer is, 35 negative result

For the part that does not contain organic matter your answer is, 60 positive result

Step-by-step explanation:

If we pay attention to the part that contains organic matter the total amount 700 and 665 is positive, so subtract them 700-665 to get 35 negative result

For the part that does not contain organic matter the total amount is 300, and 240 of it is negative, so subtract 240 from 300 to get 60 positive result

Your Welcome, Hope This Helps, And Have an Awesome Day!!!

6 0

3 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago