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Romashka-Z-Leto [24]
3 years ago
9

Rewrite using Radicals

Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0

Answer:

cannot be put into radical form, sorry!

Step-by-step explanation:

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Aliza plays basketball every Tuesday and
Lemur [1.5K]

Answer:

4 days

Step-by-step explanation:

June starts on Monday

for 30days we have 4 weeks starting from Monday to Sunday and extra 2 days which are Monday and Tuesday

so we have 5 mondays and tuesdays

4 wed, thu, fri, sat, sun

Aliza played piano on june1 monday

So aliza played basketball on 5 tues + 4 thurs = 9 days

for calculating both basketball and paino

piano day should be on tuesday or thursday

from the below picture u can see pink dots are piano days

and yellow circles are both piano and basketball days

so on alternate weeks they are coinciding

so there are 4 days

3 0
2 years ago
Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).
bija089 [108]

<em>Note: Since you missed to mention the the expression of the function </em>p(x)<em> . After a little research, I was able to find the complete question. So, I am assuming the expression as </em>p(x)=x^4-9x^2-4x+12<em> and will solve the question based on this assumption expression of  </em>p(x)<em>, which anyways would solve your query.</em>

Answer:

As

p\left(-2\right)=0

Therefore, x=-2 is a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12

As

p\left(2\right)=-16

Therefore, x=2 is not a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12

Step-by-step explanation:

As we know that for any polynomial let say<em> </em>p(x)<em>, </em>c is the root of the polynomial if p(c)=0.

In order to find which of the given values will be a root of the polynomial, p(x)=x^4-9x^2-4x+12<em>, </em>we must have to evaluate <em> </em>p(x)<em> </em>for each of these values to determine if the output of the function gets zero.

So,

Solving for p\left(-2\right)

<em> </em>p(x)=x^4-9x^2-4x+12

p\left(-2\right)=\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12

\mathrm{Simplify\:}\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12:\quad 0

\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12

\mathrm{Apply\:rule}\:-\left(-a\right)=a

=\left(-2\right)^4-9\left(-2\right)^2+4\cdot \:2+12

\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}

=2^4-2^2\cdot \:9+8+12

=2^4+20-2^2\cdot \:9

=16+20-36

=0

Thus,

p\left(-2\right)=0

Therefore, x=-2 is a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12<em>.</em>

Now, solving for p\left(2\right)

<em> </em>p(x)=x^4-9x^2-4x+12

p\left(2\right)=\left(2\right)^4-9\left(2\right)^2-4\left(2\right)+12

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

p\left(2\right)=2^4-9\cdot \:2^2-4\cdot \:2+12

p\left(2\right)=2^4-2^2\cdot \:9-8+12

p\left(2\right)=2^4+4-2^2\cdot \:9

p\left(2\right)=16+4-36

p\left(2\right)=-16

Thus,

p\left(2\right)=-16

Therefore, x=2 is not a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12<em>.</em>

Keywords: polynomial, root

Learn more about polynomial and root from brainly.com/question/8777476

#learnwithBrainly

7 0
3 years ago
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M=x^3+y^2-6(x-y)-2021
bagirrra123 [75]

Answer:

Step-by-step explanation:

m=x^3+y^2-6(x-y)-2021

distribute: 6x-6y

now you have m=x^3 + y^2 - 6x - 6y - 2021

7 0
2 years ago
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The graph below shows a proportional relationship between y and x. What is the constant of proportionality, y/x?
steposvetlana [31]

Answer:

1,40

Step-by-step explanation:

7 0
3 years ago
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Brian’s desk is 3 feet 7 inches long. Given that 1 inch is approximately 2.54 centimeters, about how many centimeters long is th
Alborosie

I hope this is right but I think It’s c

7 0
3 years ago
Read 2 more answers
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