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natita [175]
2 years ago
5

Jacki is playing a game. Her pieces end up on the circular game board. When playing the game, her score is the sum of all pieces

. How many different possible scores could Jacki get if she has 3 game pieces?
(THERE WERE NO ANSWER CHOICES )
Mathematics
2 answers:
Alex_Xolod [135]2 years ago
3 0

i think 2,1,3 but that is just my opinion

Kitty [74]2 years ago
3 0
1,2,3 that’s why I thing I don’t know if it’s right
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15

Step-by-step explanation:

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Jared has a wooden board that is 11 ft long. He wants to cut it into two pieces so that the longer piece is 4 ft less than 4 tim
ivann1987 [24]

Answer

Find out the length of the shorter and longer pieces of a board .

To prove

Let us assume that the length of the shorter pieces be x.

As given

Jared has a wooden board that is 11 ft long.

He wants to cut it into two pieces so that the longer piece is 4 ft less than 4 times the length of the shorter piece.

Than the length of the longer pieces = 4x - 4

Than the equation becomes

x + 4x - 4 = 11

5x = 11 + 4

5x = 15

x = \frac{15}{5}

x = 3 ft

Therefore the length of the shorter pieces be 3 ft .

The length of the longer pieces  = 4x - 4

                                                      = 4 × 3 - 4

                                                      = 12 - 4

                                                      = 8 ft

Therefore the length of the longer pieces be 8 ft .



5 0
3 years ago
If p is the incenter of triangle jkl, find each measure
Hunter-Best [27]

Answer:

PO = 7

PM = 7

MJ = 11

∠PJO = 32°

∠KJL = 64°

PL ≈ 18.385

OL = 17

∠PLO = 22°

∠NLO = 44°

∠JKL = 72°

∠MKP = 36°

∠NKP = 36°

∠PKN = 36°

KN = 10

PL ≈ 13.04

PK ≈ 12.21

JL = 28

JK = 21

LK = 27

Step-by-step explanation:

The given parameters are;

The point representing the incenter of the triangle = P

Therefore PO = PM = PN = 7

tan(32°) = PM/JM = 7/JM

∴JM = 7/(tan(32°)) ≈ 11.2

∠PJO = tan⁻¹(7/11)≈ 32.47°

∠PJO = ∠PJM = 32° similar triangles

∠KJL = ∠KJP + ∠PJO = 32 + 32 = 64°

∠KJL ≈ 64°

PL = √(7² + 17²) ≈ 18.385

OL = NL = 17 similar triangles

∠PLO = sin⁻¹(7/18.385) ≈ 22.380°

∠PLO = ∠PLN = 22°

∠NLO = ∠PNL + ∠OLP ≈ 22° + 22° ≈ 44°

∠NLO ≈ 44.380°

∠JKL = 180 - (∠KJL + ∠NLO)

∠JKL = 180° - (64° + 44°) ≈ 72°

∠JKL  ≈ 72°

∠MKP = ∠NKP = 72°/2 = 36°

∠MKP = 36°

∠NKP = 36°

∠PKN = ∠JKL - ∠MKP = 72° - 36° ≈ 36°

∠PKN  ≈ 36°

KN = KM = 10

MJ = OJ = 11

PL = √(7² + 11²) ≈ 13.04

PK = √(7² + 10²) ≈ 12.21

JL = JO + OL = 11 + 17 = 28

JK = JM + MK = 11 + 10 = 21

LK = LN + NK = 17 + 10 = 27

6 0
2 years ago
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