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2 years ago

5

Jacki is playing a game. Her pieces end up on the circular game board. When playing the game, her score is the sum of all pieces

. How many different possible scores could Jacki get if she has 3 game pieces?
(THERE WERE NO ANSWER CHOICES )

2 answers:

Alex_Xolod [135]2 years ago

3 0

i think 2,1,3 but that is just my opinion

Kitty [74]2 years ago

3 0

1,2,3 that’s why I thing I don’t know if it’s right

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THE PICTURE Is Up THERE PLEASE HELP ME WTHH

Damm [24]

The last one i think

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3 years ago

Apply Gaussian quadrature with n = 4 to approximate integrate sin x^2dx from 1 to 5

maks197457 [2]

First, recall that Gaussian quadrature is based around integrating a function over the interval [-1,1], so transform the function argument accordingly to change the integral over [1,5] to an equivalent one over [-1,1].

$x=2t+3\iff t=\dfrac x2-\dfrac32\implies2\mathrm dt=\mathrm dx$
$x=1\implies t=\dfrac{2-6}4=-1$
$x=5\implies t=\dfrac{10-6}4=1$

So,

$\displaystyle\int_{x=1}^{x=5}\sin x^2\,\mathrm dx=\displaystyle2\int_{t=-1}^{t=1}\sin(2t+3)^2\,\mathrm dt$

Let $f(t)=2\sin(2t+3)^2$ . With $n=4$ , we're looking for coefficients $c_i$ and nodes $x_i$ , with $1\le i\le4$ , such that

$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx c_1f(x_1)+\cdots+c_4f(x_4)$

You can either try solving for each with the help of a calculator, or look up the values of the weights and nodes (they're extensively tabulated, and I'll include a link to one such reference).

Using the quadrature, we then have

$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.3749f(-0.8611)+0.6521f(-0.3400)+0.6521f(0.3400)+0.3749f-0.8611)$
$\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.5790$

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3 years ago

Help Please I Need Help

Ket [755]

Answer:

<u>Linear:</u> "You start with $3 and save $1 each month."

<u>Quadratic:</u> "Your total savings is 3 times the number of months multiplied by itself."

<u>Exponential:</u> "You save $3 the first month, and then each month the amount triples."

Explanation: I did the work. :)

<em>PLEASE MARK BRAINLIEST!</em>

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4 years ago

NEED HELP ASAP!!!

Sergeeva-Olga [200]

Answer:

(b) $P(\textrm{Event of getting a 3 in the spinner)} = \frac{11}{61}$

Step-by-step explanation:

Let E: Event of getting a 3 in the spinner.

So, the number of favorable outcomes = 11

Total number of outcomes = Number of times the outcomes is {1,2,3,4,5,6}

= {13 +10 +11+16+11} = { 61}

So, the total number of outcomes = 61

$\textrm{Probability of Event E} = \frac{\textrm{Number of favorable events}}{\textrm{Total number of outcomes}}$

So, here $P(\textrm{Event of getting a 3 in the spinner)} = \frac{11}{61}$

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3 years ago

Pythagorean Thereom

Ratling [72]

My answer would be 14 miles. I really hope this is what you need

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3 years ago