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3 years ago

8

Problem Situation: Amy's cable company charges her a $75 installation fee and $89 per month for cable services. She has had cabl

e services for 10 months. How much has she paid in total for cable services?
You can use a letter to represent an unknown quantity. Use the drop-down menus to complete the statements below.

The unknown quantity is the
.

A letter to stand for that quantity is

1 answer:

siniylev [52]3 years ago

6 0

Answer:

890+ 75

Step-by-step explanation:

89× 10= 890

+ 75 installation fee

= 965

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kicyunya [14]

For both of these, we will divide the wanted outcome by the number of possible outcomes. We will end up with a decimal. A decimal multiplied by 100 becomes a percent.

[a] 50%

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[b] 52%

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2 years ago

If ab = 9 and a² + b² = 81, then (a+b)² = ?

Andre45 [30]

Answer:

99

Step-by-step explanation:

Through some clever algebra, we can combine our first two equations using the fact that

$(a+b)^2=a^2+2ab+b^2$

We have the a² and the b² in the equation $a^2+b^2=81$ , and we <em>almost </em>have a 2ab in the equation $ab=9$ . To get that 2ab, we can simply double both sides of the first equation to get $2ab=18$ . From there, we'll add the first two equations together, giving us the summed equation

$a^2+b^2+2ab=81+18\\a^2+2ab+b^2=99$

And since $(a+b)^2=a^2+2ab+b^2$ , we can equivalently say that

$(a+b)^2=99$

5 0

3 years ago

If you predict the population of Hamilton County in 2003, are you interpolating or extrapolating?

Hitman42 [59]

Given,

The population of the county in 2000 is 844.

The population of the county in 2009 is 856.

The population of the county in 2015 is 810.

Here, the population of 2000 and 2009 is given.

As known, the value changes linearly between two points.

When the value changes linearly between two points, then value of point between given points can be obtained by interpolation.

Hence, to predict the population of county interpolation is used.

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1 year ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago

Write an addition equation that can help you find 9-3

Alborosie

X+3=9
-3 -3
________
X=3

7 0

3 years ago

Read 2 more answers