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Flura [38]
3 years ago
12

A model giraffe has a scale of 1 in : 3 ft. If the real giraffe is 12 ft tall, then how tall is the model giraffe? someone teach

me how to do this please
Mathematics
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

4 inchess

Step-by-step explanation:

first you divide 12 ft by 3 ft to get the rate which is 4

then mulitply is by 1 in to get 4 inches

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Step-by-step explanation:

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2 years ago
If a translation maps ∠I onto ∠K, which of the following statements is true?
jonny [76]

The statement which is true is  ΔGHI ~ ΔGJK.

<h3>What is Translation?</h3>

This is commonly used in geometry to describe a function which moves object at distances.

This therefore means that translation of ∠I onto ∠K means shifting of point I to point K.

The triangles given are HGI and JGK.

Translation in this scenario therefore means that the triangles are similar only if other angles are mapped to their corresponding angles.

It confirms that ΔGHI ~ ΔGJK thereby making it the most appropriate choice.

Read more about Translation here brainly.com/question/16253702

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2 years ago
The sum of two numbers is 32 and their difference is 8 what are the two numbers
Likurg_2 [28]
A+b=32
a-b=8

let's subtract bottom equation from the top:

a+b-(a-b)=32-8
2b=24
b=12

Then a=20
4 0
3 years ago
Who can prove that ? :D<br><br> prove that lim x about 0 (sin(x)/x)=1<br> by using sandwich theorem
earnstyle [38]
cos (x)  \leq \frac{sin (x)}{x}  \leq 1

Apply limit as x->0
8 0
3 years ago
The polynomial has the following zeros: 0, 1, -2i, 3+the square root of 3. Put the polynomial in standard form.
dimulka [17.4K]
Standard form
ok, so the factored form of a polynomial with roots r1,r2,r3,r4 is
f(x)=(x-r1)(x-r2)(x-r3)(x-r4)
so
since the roots are 0,1,-2i,3+√3
I am assuming you want real coefients so ince -2i is a root, 2i is also a root

f(x)=(x-0)(x-1)(x+2i)(x-2i)(x-(3+√3))
f(x)=x⁵-(√3)x⁴-4x⁴+(√3)x³+7x³-(4√3)x²-16x²+12x

if you were allowed to have no-real coefients then exclue the 2i
f(x)=(x-0)(x-1)(x+2i)(x-(3+√3))
f(x)=(4x^4-4x^3- \sqrt{3}x^3+\sqrt{3}x^2+3x^2)+(2x^3-8x^2-2 \sqrt{3}x^2+6x+2 \sqrt{3}x) i
6 0
3 years ago
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