Slope of -4 and goes through (-5,1)
1 answer:
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Let
where we assume |r| < 1. Multiplying on both sides by r gives
and subtracting this from gives
As n → ∞, the exponential term will converge to 0, and the partial sums will converge to
Now, we're given
We must have |r| < 1 since both sums converge, so
Solving for r by substitution, we have
Recalling the difference of squares identity, we have
We've already confirmed r ≠ 1, so we can simplify this to
It follows that
and so the sum we want is
which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?
Answer:
Step-by-step explanation:
f(x) = (x - 2)(x - 5)x(x+ 7)
f(x) = (x^2 - 7x + 10)*x * (x + 7)
f(x) = x(x^3 - 39x + 70)
f(x) = x^4 - 39x^2 + 70x
To show that this is correct, I've made a graph with these points labeled. The graph is just around the x axis. The local maximums and minimums are just too large a value.
