Answer:
A = 3
B = -5
C = 2
Step-by-step explanation:
The way to format a quadratic equation is:
, so the first step to solving this is to format it in the right way, where the
comes first, the
second, and the number alone.
After formatting, your equation should look like this: 
From here, you can see the the <em>a </em> is 3, the <em>b</em> is -5, and the <em>c </em>is 2
Santosh's cousin is 15 years old because 49-4=45. Divide 45 by 3 and the quotient is 15. To check: 15 times 3= 45. Add 4 and the sum is 49.
The answer is c bc I just know
Answer:

Step-by-step explanation:

For positive rate of change 

Answer:
30 ft
Step-by-step explanation:
We can use ratios
3 6
------ = ------------
15 x
Using cross products
3x = 6*15
Divide each side by 3
3x/3 = 6*15/3
x = 30