Let
x---------> the length of the first piece
y---------> the length of the second piece
z---------> the length of the third piece
we know that
x+y+z=72 -------> equation 1
y=x+6 -----> solve for x
x=y-6 -------> equation 2
z=6+y -------> equation 3
substitute equation 2 and equation 3 in equation 1
[y-6]+y+[6+y]=72
3y=72
y=(72/3)=24 in
<u>Find the value of x</u>
x=y-6 -------> equation 2
x=24-6=18 in
<u>Find the value of z</u>
z=6+y -------> equation 3
z=6+24=30 in
therefore
<u>the answer is</u>
the length of the first piece is 18 in
the length of the second piece 24 in
the length of the third piece is 30 in
3miles to my friends house
Answer:
(1.5,0)
(.5,0)
Step-by-step explanation:
Quadratic formula below
We first need to move everything to one side of the equation
4x²-8x+3=0
Then plug everything in
(8±√(-8²-4*4*3))/(2*4)
(8±√16)/8
To calculate the ± we need to do when where it's adding and then negative
we have
(8+4)/8=3/2
and hten
(8-4)/8=1/2
Answer:
B. 14 hope this helps
Step-by-step explanation:
