The answer to this question is phase. These three properties, amplitude, frequency and phase are basic properties of waves. Frequency refers to the number of cycles per second, amplitude refers to the strength, and phase is the position of the wave on the time axis.
It pulls towards it until it gets to a certain point and pushes away and so it stays in a steady orbit
Based on the data provided, we can conclude that the graph in question corresponds to the K-selected theory in regards to the human species.
When considering the data of certain species and grouping them into categories such as extinct, endangered, or K/r-selected we take into account factors such as:
- Population size
- Behavior
- Carrying capacity
- Reproduction rates
and so on, then classify each species accordingly.
Species that are Extinct are no longer on the earth. This classification refers to species of the past and does not include humans as of yet. The endangered category is reserved for species whose population sizes are <u>at a critical low and are near </u><u>extinction</u>, which is also not the case for humans.
The K-selected and r-selected theories consider reproduction rates and carrying capacity as well when grouping species. Species that produce few offspring at a time are often found in this group. This category also refers to species whose offspring have a high chance of survival into maturity and whose population size is near the limit of the environment. All of this follows the data given and is the classification for the human species.
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B. Pine trees, this is the answer that was right after I took the test XD
Answer:
0.153
Explanation:
We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.
So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.
ρVg = ρ'V'g + ρ"V"g
ρV = ρ'V'g + ρ"V"
Its new body volume = volume of water displaced, V = V' + V"
ρ(V' + V") = ρ'V' + ρ"V"
ρV' + ρV" = ρ'V' + ρ"V"
ρV' - ρ"V' = ρ'V" - ρV"
(ρ - ρ")V' = (ρ' - ρ)V"
V'/V" = (ρ - ρ")/(ρ' - ρ)
= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)
= (0.9988 g/cm³ ÷ 0.18 g/cm³)
V'/V" = 5.55
Since V = V' + V"
V' = V - V"
(V - V")/V" = 5.55
V/V" - V"/V" = 5.55
V/V" - 1 = 5.55
V/V" = 5.55 + 1
V/V" = 6.55
V"/V = 1/6.55
V"/V = 0.153
So, the fish must inflate its air sacs to 0.153 of its expanded body volume
