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juin [17]
3 years ago
9

Which set of ordered pairs does not represent a function?

Mathematics
1 answer:
Leokris [45]3 years ago
4 0
The last one does not represent a function because for it to be a function none of the x’s can repeat and in the last one the 0 repeats.
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Write x2-8+13=0 in the form (x-a)2=b
egoroff_w [7]

Answer:

(x-4)2=-13

Step-by-step explanation:

2x+13=8

2x-8=-13

2(x-4)=-13

7 0
3 years ago
Logan wants to have $130,000 to pay for a surgery on his retractable forearm claws in 30 months. If he can invest money in an ac
dangina [55]

Answer: $107,836.69 or about $107,837 (to the nearest dollar)

Step-by-step explanation:

Formula to the  accumulated amount received after investing principal amount (P) at rate of interest (r) compounded monthly for t months :

A=P(1+\dfrac{r}{12})^{t}

As per given , A = $130,000

r= 7.5% = 0.075

t= 30 months

Now,

130000=P(1+\dfrac{0.075}{12})^{30}\\\\\Rightarrow 130000=P(1+0.00625)^{30}\\\\\Rightarrow 130000=P(1.00625)^{30}\\\\\Rightarrow 130000=P \times1.20552661036\\\\\Rightarrow\   P=\dfrac{130000}{1.2055266}=107,836.69

Hence he need to invest $107,836.69 .

8 0
3 years ago
Use the rules of exponents to evaluate or simplify. Write without negative exponents. 1/4^-1/2 = ___ a0
Nastasia [14]

For this case we have, by definition:


a^{-b} =\frac{1}{a ^ b}

So, we have:


\frac{1}{4}^{-\frac{1}{2}}=\frac{1}{(\frac{1}{4})^{\frac{1}{2}}}

On the other hand we have that by definition:


a^{\frac{1}{2}}=\sqrt{a}

Thus, the expression can be written as:


\frac{1}{\sqrt {\frac{1}{4}}} =

\frac{1}{\frac{1}{\sqrt{4}}}

\frac{1}{\frac{1}{2}}

\frac{1*2}{1*1}=2

So, we have:


\frac{1}{4}^{-\frac{1}{2}}= 2

Answer:


\frac{1}{4}^{-\frac{1}{2}}= 2


4 0
3 years ago
Question 2 (10 points)
lara [203]

Answer:

140-111=29

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Kajal holds a ruler in some wavy water. The depth of the water t seconds after she starts measuring it, in cm, is given by D(t)=
Vera_Pavlovna [14]

Answer:

t = 0.77

Step-by-step explanation:

D(t) = 50 - 23 sin(π(t + 0.23))

The value of the sine function has a maximum of -1 and a minimum of 1.

The average value of the sine function is 0.

At maximum sine value:

D(t) = 50 - 23(1) = 50 - 23 = 27

At minimum sine value:

D(t) = 50 - 23(-1) = 50 + 23 = 73

At average sine value of 0:

D(t) = 50 - 23(0) = 50 - 0 = 50

The average depth of the waves is 50 cm.

Now we need to find at what time, t, that occurs.

D(t) = 50 - 23 sin(π(t + 0.23)) = 50

50 - 23 sin(π(t + 0.23)) = 50

-23 sin(π(t + 0.23)) = 0

sin(π(t + 0.23)) = 0

The value of the sine is 0 at 0, π, 2π, ..., nπ

π(t + 0.23) = nπ

t + 0.23 = n

t = n - 0.23

n is all integers, but here we are concerned with the first occurrence after time equals zero, so we want n = 1.

t = 1 - 0.23

t = 0.77

8 0
3 years ago
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