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aleksley [76]
3 years ago
11

Help with these equations please!

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0
1) yes
2) x=-4,y=-7
3) x= -3, y=4
4) x= -1, y=2
5) x= -5, y=-8
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cool question I love it

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-1000x^3 hope this helps

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Use the slope-intercept form to Graph y=-1/8x+2
noname [10]

Step-by-step explanation:

This is a straight line equation. We only need two points to draw a straight line.

Choose two different numbers, put them into the equation instead of x, and calculate the value of y.

y=-\dfrac{1}{8}x+2

for x = 8

y=-\dfrac{1}{8}\cdot8+2=-\dfrac{8}{8}+2=-1+2=1

<h2>(8, 1)</h2>

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Mark the points in the coordinate system and draw a straight line through the given points.

<em>(look at the attachment)</em>

4 0
3 years ago
PLEASE HELP ASAP PLEASE ANSWER CORRECTLY WILL GET BRAINLIEST
Xelga [282]

Answer:

True

Step-by-step explanation:

Each x input has 1 y output

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3 years ago
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i have been trying to solve this compound and double angle question please help me find the answer to these question guys​
natali 33 [55]

Answer:

These type of questions are super tricky b/c you have to remember all the different versions of the identities, and then they put the question in some odd form,  I feel like this should land math professors in jail , for dishonesty , b/c it's really a form of "how tricky can I make a question and still have a way to solve it"   anyway,

Step-by-step explanation:

a)

next the question asks   1-cos 2A   and this is total abuse of notation.   the way this should be written is   1- cos( 2A)  so we know that the A is part of the cosine functions input... btw.. in any computer program,  it would never ever let you get away with that top form of the expression.  :/   anyway... I keep ranting.. huh... sorry  :P

1-cos(2A) is an odd form of the identity  1/2(1-cos(2A) = sin^{2}(A)  the 1/2 is missing but we can add that pretty easy, we just have to remember to take it out too. I usually forget to do that. and my professor marks me off completely,  totally wrong, but I just miss one small thing  :/  anyway....

our 1-cos(2A) needs the 1/2 added to it.  or if we move that 1/2 to the other side it looks like  2*sin^{2}(A)  = 1-cos(2A)  and this is that "odd" from of the identity that I was talking about.  

next let's deal with sin(2A)  it has an identity of  2 sin(A)cos(A) which is really nice for us b/c it will cancel out the 2 in then numerator for us, nice !

now our fraction looks like  [2* sin^{2}(A)] / 2 sin(A)cos(A)

so cancel out one of the sines

2*sin(A) / 2 cos(A)

cancel the 2s

Sin(A) / Cos(A) = Tan(A)

nice  it worked out  :P

b)

by the above that we just worked out, then

Tan(15) = Sin(15) / Cos(15)

I had to look up what sin of 15 is b/c it's not one of those special angles but it does have an exact form of

Sin(15) = (√3 - 1) / 2√2

Cos(A) = (√3 + 1) / 2√2

you can use rule of Cos(A-B) = Cos(A)Cos(B)+Sin(A)Sin(B) to get the above and a similar rule for Sin(A-B)

back to our problem,  the 2√2 will cancel out

then we have

Tan(15) =  (√3 - 1) /(√3 + 1)

in the form that is above that's exact, the roots could be approximated but i'll just leave that in the form that is exact.  Most math professors like that form.  

 

4 0
2 years ago
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