2\0.1 x 10\10 = it would help me a lot

The lengths of the sides of the triangle are 3, 8, and 10. Is the triangle a right triangle, acute triangle, or an obtuse triang

weqwewe [10]

Answer:

Obtuse

Step-by-step explanation:

You have to make sure it is a triangle by adding the smallest and the medium sides, if the result is greater than the bigger side then it is a triangle.
you then use the Pythagorean theorem to check if the triangle is a right triangle, acute, or obtuse. If $c^{2}$ = $a^{2} +b^{2}$ then it is a right triangle. If $c^{2} >a^{2} + b^{2}$ then it is an obtuse triangle. if $c^{2} < a^{2} +b^{2}$ then it is an acute triangle.

$10^{2}$ _ $3^{2} + 8^{2}$
9+64_100
70_100
70<100

in this case $c^{2}$ is greater than $a^{2} +b^{2}$ therefore, is it an obtuse triangle.

3 0

2 years ago

What values of x make the equation x2 + 9x – 22 = 0 true? Check all that apply. –11 –2 0 2 11

Marat540 [252]

Answer: x = 2 ; -11 .
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Explanation:
_____________________________________________
Given the equation:
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x² + 9x − 22 = 0 ; Solve for: "x" ;
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Let us factor the "left-hand side" of the equation:
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"x² + 9x − 22" ;
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What are the factors of "-22"" that add up to "positive 9" ?
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Let us list the factors of "-22" :
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-2, 11; → -2 + 11 = 9 ;
-11, 2; → -11 + 2 = -9 ;
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So we have: "-2" and "11" ;
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So; "x² + 9x − 22" ; factors into " (x−2)(x + 11)" ;
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We have: (x−2)(x + 11) = 0 ;

So: x − 2 = 0 ;

Add "2" to each side of the equation;

x − 2 + 2 = 0 + 2 ;

x = 2 ;
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x + 11 = 0 ;

Subtract "11" from each side of the equation;

x + 11 − 11 = 0 − 11 ;

x = -11 ;
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Answer: x = 2 ; -11 .
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6 0

3 years ago

Which one of the pairs of angles below is adjacent?

Norma-Jean [14]

Adjacent angles are angles that are next to each other and share a common vertex and a common side.

7 0

2 years ago

What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a

Anarel [89]

Answer:

Average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: $f(x)= x^2-x-1$

The formula used to find average rate of change is:

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}$

We have, a = -1 and b = 1

Finding f(b) when b=1

$f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1$

Now, finding f(a), when a= -1

$f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1$

Now, putting values and finding average rate of change

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1$

So, average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

4 0

3 years ago

The graph below shows the solution to which system of inequalities. y>-3 and y<-x

irina1246 [14]

Answer: (should be) A

Step-by-step explanation: I've done the same test before

8 0

3 years ago