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anastassius [24]
3 years ago
14

Expand and simplify (x + 3)(x-4)

Mathematics
2 answers:
Hunter-Best [27]3 years ago
5 0

Answer:

2x -1

Step-by-step explanation:

x*x =2x 3-4 =-1

2x+-4

sweet [91]3 years ago
4 0
Answer: x^2x-12 (by the way ^2 is a square)
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A circle is centered at the point (5, -4) and passes through the point (-3, 2).
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Find all solutions by transforming the system to reduced echelon form and back substituting. (If there are an infinite number of
Zolol [24]

Answer:

The system has infinite solutions described in the set \{(x_1,x_2,x_3)=(6+s1, -10-2s1,s1): s1\in\mathbb{R}\}

Step-by-step explanation:

The augmented matrix of the system is \left[\begin{array}{cccc}-1&-1&-1&4\\2&1&0&2\end{array}\right].

We apply row operations:

1. We add the first row to the second row twice and obtain the matrix \left[\begin{array}{cccc}-1&-1&-1&4\\0&-1&-2&10\end{array}\right]

2. multiply by -1 the rows of the previous matrix and obtain the matrix \left[\begin{array}{cccc}1&1&1&-4\\0&1&2&-10\end{array}\right] that is the reduced echelon form of the matrix associated to the system.

Now we aply backward substitution:

1. Observe that the reduced echelon form has a free variable, then the system has infinite solutions.

2.

x_2+2x_3=-10\\x_2=-10-2x_3

3.

x_1+x_2+x_3=-4\\x_1-10-2x_3+x_3=-4\\x_1-x_3=-4+10\\x_1=6+x_3.

Then the set of solutions is \{(x_1,x_2,x_3)=(6+s1, -10-2s1,s1): s1\in\mathbb{R}\}

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The formula for the area of a triangle is 1/2bh=A. Which of the following is not a possible first step to rearrange this formula
yarga [219]

We want to put b alone on one side of the equation.

If we multiply by 1/2, we get 1/4bh = A/2. Not only did we not remove a variable from the left side, we made it even more complicated.

So the answer is A.

7 0
3 years ago
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