Question

What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down? Drag numbers to complete the coordinates. Numbers may be used once, more than once, or not at all. A coordinate plane with three trapezoids. Trapezoid A B C D has coordinates A 1 comma 1, B 2 comma 3, C 4 comma 3, and D 5 comma 1. –5–4–3–2–112345 A'( , ), B'( , ), C'( , ), D'( , )

Answer 1

Answer:

$A" =(-1,-1)$    $B" =(-2,1)$

$C" =(-4,1)$    $D" =(-5,-1)$

Step-by-step explanation:

Given

$A = (1,1)$        $B =(2,3)$

$C = (4,3)$        $D = (5,1)$

Required

The new coordinates after reflected across y-axis and shifted 2 units down

When a point is reflected across the y-axis, the rule is:

$(x,y)=>(-x,y)$

So:

$A = (1,1)$ $=> A' = (-1,1)$

$B =(2,3)$ $=> B' = (-2,3)$

$C = (4,3)$ $=> C' = (-4,3)$

$D = (5,1)$ $=> D' = (-5,1)$

When a point is translated 2 units down, the rule is:

$(x,y) => (x,y-2)$

So:

$A = (1,1)$ $=> A' = (-1,1)$ $=> A" =(-1,-1)$

$B =(2,3)$ $=> B' = (-2,3)$ $=> B" =(-2,1)$

$C = (4,3)$ $=> C' = (-4,3)$$=> C" =(-4,1)$

$D = (5,1)$ $=> D' = (-5,1)$ $=> D" =(-5,-1)$

So, the new coordinates are:

$A" =(-1,-1)$    $B" =(-2,1)$

$C" =(-4,1)$    $D" =(-5,-1)$