3 years ago

Find the equation of the line through the point (-2,-2) that is perpendicular to the line y=2x-1

1 answer:

Lerok [7]3 years ago

5 0

A line perpendicular to y = 2x - 1 must have the slope -1/2 (negative reciprocal of 2).

Thus, the eq'n of the new line is y+2 = (-1/2)(x+2).

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stiv31 [10]

Answer:

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Step-by-step explanation:

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Therefore,

$r=\sqrt {I}+10$

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Schach [20]

Answer:

domain: [-3,2]

range: [-3,2]

Step-by-step explanation:

domain: all possible x values *maximum values of x

range: all possible y values *maximum values of x

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Furkat [3]

4n+7−(7n−8)

=4n+7+−1(7n−8)

=4n+7+−1(7n)+(−1)(−8)

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