Ask question

Ask question

All categories

3 years ago

13

A plumber charges $25 for a service call plus $50 per hour of service write an equation to represent the cost of hiring this plu

mber

1 answer:

notka56 [123]3 years ago

8 0

Answer:

$(25 + 50h)

Step-by-step explanation:

Cost = 25 + 50h

Where 'h' is the number of hours of service

8 hours of work: h = 8

Cost = 25 + 50(8) = $425

10 hours of work: h = 10

Cost = 25 + 50(10) = $525

You might be interested in

Anyone with a knee injury or any doctor! What does it mean if my knee popped locked up all in like 1.5 seconds and then it now h

hodyreva [135]

Answer:

Well I recently tore my meniscus a little bit, but you said yours popped/locked, I don't think mine did that. But it could be a bigger meniscus tear then mine, don't take my word for it tho, I'm no orthopedic or doctor. And for the second time in 7-9 months?? I'd definitely go get that checked out if you can.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Simplify the expression:<br><br> 3x (4x-6)<br> —————<br> 2x(3x)

Marina86 [1]

Answer:

$=\frac{2x-3}{x}$

Step-by-step explanation:

$=6x^2\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=\frac{3x\left(4x-6\right)}{2x\cdot \:3x}\\2x\cdot \:3x=6x^2\\=\frac{3x\left(4x-6\right)}{6x^2}\\\mathrm{Cancel\:}\frac{3x\left(4x-6\right)}{6x^2}:\quad \frac{4x-6}{2x}\\=\frac{4x-6}{2x}\\\mathrm{Factor}\:4x-6:\quad 2\left(2x-3\right)\\=\frac{2\left(2x-3\right)}{2x}\\\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1\\=\frac{2x-3}{x}$

7 0

3 years ago

In two or more complete sentences, explain how to solve the cube root equation, <img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3

nordsb [41]

Isolate the root expression:

$\sqrt[3]{x+1}+2=0\implies\sqrt[3]{x+1}=-2$

Take the third power of both sides:

$\sqrt[3]{x+1}=-2\implies(\sqrt[3]{x+1})^3=(-2)^3$

Simplify:

$(\sqrt[3]{x+1})^3=(-2)^3\implies x+1=-8$

Isolate and solve for $x$ :

$x=-9$

Since the cube root function is bijective, we know this won't be an extraneous solution, but it doesn't hurt to verify that this is correct. When $x=-9$ , we have

$\sqrt[3]{-9+1}=\sqrt[3]{-8}=\sqrt[3]{(-2)^3}=-2$

as required.

5 0

3 years ago

Please help urgentttttttt

Kruka [31]

Answer:

The best answer would be C

Step-by-step explanation:

The square has two parallel lines and the rhombus has parallel lines as well. And when you turn the square, it looks like a rhombus. They are both parallelograms and quadrilaterals.

Hope this helps

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cint%7B%5Bsin%289x%29cos%289x%29%5D%7D%20%5C%2C%20dx" id="TexFormula1" title="\int{[sin(9x)c

Sladkaya [172]

Recall the double angle identity,

sin(2x) = 2 sin(x) cos(x)

Then we can write

sin(9x) cos(9x) = 1/2 sin(2 • 9x) = 1/2 sin(18x)

Then

∫ sin(9x) cos(9x) dx

= 1/2 ∫ sin(18x) dx

= -1/2 • 1/18 cos(18x) + C

= -1/36 cos(18x) + C

though you could continue with another double angle identity,

cos(2x) = cos²(x) - sin²(x)

to rewrite the antiderivative as

= -1/36 (cos²(9x) - sin²(9x)) + C

= 1/36 (sin²(9x) - cos²(9x)) + C

5 0

2 years ago