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Anit [1.1K]
3 years ago
5

15 point to the one that answers

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0
If you use PEMDAS, you’ll start with multiplication. so 54*96=5,184. 6*2=12.
so now the problem would be 96+5,184+32/98-12.
from here you would divide.
so, 32/98=0.33 (rounded up)
now you add.
96+5,184+0.33=5,280.33
so, 5,280.33-12=5,268.33.
the answer is:
5,268.33
hope this helped!!
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Enter the value for x that makes the equation √x-7=-4
Agata [3.3K]

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Step-by-step explanation:

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4 0
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i don't understand how to make it into a graphing form? how do you find the center and radius? (I'm confused because it has a 4x
Vilka [71]

Answer: \bold{(x-2)^2+(y-3)^2=\dfrac{1}{4}}

               Center = (2, 3)          radius = \bold{\dfrac{1}{2}}

<u>Step-by-step explanation:</u>

When both the x² and y² values are equal and positive, the shape is a circle. Complete the square to put the equation in format:

(x-h)² + (y-k)² = r²    where

  • (h, k) is the vertex
  • r is the radius

1) Group the x's and y's together and move the number to the right side

   4x² - 16x         + 4y² - 24y               = -51        

2) Factor out the 4 from the x² and y²

    4(x² - 4x          ) + 4(y² - 6y            ) = -51

3) Complete the square (divide the x and y value by 2 and square it)

    4[x^2-4x+\bigg(\dfrac{-4}{2}\bigg)^2]+4[y^2-6y+\bigg(\dfrac{-6}{2}\bigg)^2]=-51+4\bigg(\dfrac{-4}{2}\bigg)^2+4\bigg(\dfrac{-6}{2}\bigg)^2

  = 4(x - 2)² + 4(y - 3)² = -51 + 4(-2)² + 4(-3)²

  = 4(x - 2)² + 4(y - 3)² = -51 + 4(4) + 4(9)

  = 4(x - 2)² + 4(y - 3)² = -51 +  16  +  36

  = 4(x - 2)² + 4(y - 3)² = 1

4) Divide both sides by 4

   (x-2)^2+(y-3)^2=\dfrac{1}{4}

  • (h, k) = (2, 3)
  • r=\dfrac{1}{2}

6 0
3 years ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
polet [3.4K]

Recall: SOHCAHTOA

Sin M = Opp/Hyp

Reference angle = M

Opp = 3√/21

Hyp = 15

Sin M = (3-√21)/15

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Reference angle = M

Opp = 3√21

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Tan M = √21/2

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5 0
2 years ago
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Am solving this problem correct
cestrela7 [59]
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first \ term = 3t
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third \ term = t^4

b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7

c) The degree of the polynomial is... 4
6 0
3 years ago
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