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3 years ago

Good morning can y’all help me

Mathematics

1 answer:

tatyana61 [14]3 years ago

6 0

Answer:

1/5

Step-by-step explanation:

opposite of 5x5 is 5 divided by 5

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What is the value of P(9.1)? What does it tell us about the side length and perimeter

nadya68 [22]

Answer:

the answer is 36.4

Step-by-step explanation:

you have to multiply it by 4 so it it will look like this 9.1*4=36.4

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3 years ago

Solve the system of linear equations by substitution. x=17−4y y=x−2

erik [133]

Answer:

y = x - 2

x = 17 - 4y

x = 17 - 4(x -2)

x = 17 - 4x + 8

5x = 17 + 8

5x = 25

x = 5

y = 5 - 2

y = 3

(5, 3)

Step-by-step explanation:

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4 years ago

Please help me 100 points

ValentinkaMS [17]

Answer:

p=6 Q=5 R=6

Step-by-step explanation:

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3 years ago

Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3

Maru [420]

Answer:

Fourth term: $a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{3}$ = $\sqrt{3}$

Fifth term: $a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{4}$ = 1

Sixth term: $a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}$

Step-by-step explanation:

The geometric progression is:

$9, 3 \sqrt{3}, 3...$

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

$r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}$

That is the common ratio.

Geometric progression is given generally as:

$a_n = ar^{(n - 1)}$

where a = first term

r = common ratio

$a_n$ = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: $a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{3}$ = $\sqrt{3}$

Fifth term: $a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{4}$ = 1

Sixth term: $a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}$

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3 years ago

on Saturday 2832 tourists visited the zoo on Friday 1475 tourists visited the zoo estimate the number of tourists who visited th

Maksim231197 [3]

Rounded to the nearest thousand would be 4000

6 0

3 years ago