Which number sentence shows equivalent fractions?

Find the difference and enter your answer in the space provided.<br> 1 - 14 = ?

Vinil7 [7]

Answer:

-13

Step-by-step explanation:

1 - 14 = -13

Have a great night! :)

6 0

3 years ago

Grace has a segment with endpoints C (3, 4) and D (11, 3) that is divided by a point E such that CE and DE form a 3:5 ratio. She

Dovator [93]

The answer should be 3 over 5

8 0

4 years ago

Read 2 more answers

There are 40 students in a class.

VashaNatasha [74]

Answer:

6 boys have brown hair.

Step-by-step explanation:

$40*0.6 = 24$ boys in the class.

$24 * 0.25 = 6$ boys have brown hair.

3 0

3 years ago

Read 2 more answers

Natalia has 48 tiles. Write a factor pair for the number 48

Bumek [7]

6x8=48 because if you look or know your multiplaction tables well then youll know that 6x8=48

4 0

3 years ago

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.