Answer:
The code will display the following on the screen:-
2
0
2
Explanation:
The output is like this because x{2} assigns the value 2 to the integer x.First the value of x is printed on the screen that is 2 and that newline is used to go to the next line.After that function is called doSomething with x passed as the argument. doSomething function assigns the value zero to the variable passed and prints it on the screen.So the next line is 0.Since x is passed by value so no changes will appear in the original argument.Hence the last line printed is 2.
Answer:
Hi!
Let's make a quick debug of the code:
i j Output
0+0 = 0
0+1 = 1
0+2 = 2
0+3 = 3
1+0 = 1
1+1 = 2
1+2 = 3
1+3 = 4
2+0 = 2
2+1 = 3
2+2 = 4
2+3 = 5
3+0 = 3
3+1 = 4
3+2 = 5
3+3 = 6
4+0 = 4
4+1 = 5
4+2 = 6
4+3 = 7
The total outputs is 20.
Explanation:
In the first iterations of the loop for the final value of the <em>i</em> is 1 and the final condition to stop of the do while is (<em>i</em> < 5) , so the iteration of for continues many times until <em>i</em> break the condition.
(5*4 = 20)
And after that you get 20 outputs.
I hope it's help you.
Answer:
Offer as much extraneous information as possible. The viewer will decide what is important.
Answer:
According to my physics all of functinalitys are made of angles and binary code to perform a new formula and involved to each sides....
Explanation:
HOPE IT HELPS!!!i translate into G your language
Answer:
see explaination
Explanation:
class Taxicab():
def __init__(self, x, y):
self.x_coordinate = x
self.y_coordinate = y
self.odometer = 0
def get_x_coord(self):
return self.x_coordinate
def get_y_coord(self):
return self.y_coordinate
def get_odometer(self):
return self.odometer
def move_x(self, distance):
self.x_coordinate += distance
# add the absolute distance to odometer
self.odometer += abs(distance)
def move_y(self, distance):
self.y_coordinate += distance
# add the absolute distance to odometer
self.odometer += abs(distance)
cab = Taxicab(5,-8)
cab.move_x(3)
cab.move_y(-4)
cab.move_x(-1)
print(cab.odometer) # will print 8 3+4+1 = 8
