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Burka [1]
3 years ago
10

13. Photography world has a portrait special. A

Mathematics
2 answers:
solong [7]3 years ago
7 0

Answer:

35x + 60y = 690

Why:

We need to correct number to represent X (which is 35) and Y (which is 60).

And 35x + 60y = 690, 690 being the total, fits what we need to answer.

All of the other options display an incorrect number for the X and Y values.

nalin [4]3 years ago
3 0

Answer:

35x + 60y = 690

Step-by-step explanation:

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How to calculate tarriffs?​
Ksivusya [100]

Answer:

The simple way to calculate a trade-weighted average tariff rate is to divide the total tariff revenue by the total value of imports. Since these data are regularly reported by many countries, this is a common way to report average tariffs.

3 0
3 years ago
4)
Phantasy [73]

Answer:

It’s c

Step-by-step explanation:

.1 can also be written as .10 which when you multiply by 100 is 10 so it’s also written as 10%

3 0
3 years ago
Help portfolio questions
tigry1 [53]
<span>Hello. . . I'm assuming this is the answer. . .

8x=1000000
x=125000</span>
8 0
3 years ago
3 cards are drawn from a standard deck without replacement. What is the probability that at least one of the cards drawn is a re
Rudik [331]

Answer: \dfrac{15}{17}

Step-by-step explanation:

Total number of cards in a deck = 52

Number of red cards = 26

Number of cards not red =

Number of ways to draw not red cards = ^{26}C_3

Total ways to draw 3 cards = ^{52}C_3

The probability that none of three cards are red = \dfrac{^{26}C_3}{^{52}C_3}

=\dfrac{\dfrac{26!}{3!(26-3)!}}{\dfrac{52!}{3!(52-3)!}}  [∵ ^nC_r=\dfrac{n!}{r!(n-r)!}]

=\dfrac{\dfrac{26\times25\times24\times23!}{(23)!}}{\dfrac{52\times51\times50\times49!}{3!(49)!}}=\dfrac{2}{17}

Now , the probability that at least one of the cards drawn is a red card = 1- Probability that none cards are red

=1-\dfrac{2}{17}=\dfrac{17-2}{17}=\dfrac{15}{17}

Hence, the required probability = \dfrac{15}{17}

6 0
3 years ago
Which collection of three side lengths will not form a triangle
Schach [20]
To construct a triangle, the sum of any 2 sides of the triangle should be greater than the third side of the triangle.
lets calculate the sums of all the given choices to find out which three lengths given do not form a triangle.

A.
 6,10,18
6 + 10 = 16 
16 is smaller than the third side-18
Therefore these 3 lengths do not form a triangle

B.10,12,15
10 + 12 = 22                  15+12 = 27                         15 + 10 = 25
22>15 (3rd side)            27>10 (3rd side)                    25>12 (3rd side)
In this triangle, sum of all the possible pairs of sides are greater than the third side therefore these lengths can form a triangle 

C.10,15,6
10 + 15 = 25                      15 + 6 = 21                              10+6 = 16
25 >  6                                 21>10                                      16>15
in this too, sum of all the possible pairs of sides are greater than the third side. These lengths can be used to form a triangle

D.10,18 ,12
10 + 18 = 28                      18 + 12 = 30                             10 +12 = 22
28> 12                                    30>10                                      22> 18
Therefore these lengths can also be used to form a triangle

correct answer is 6,10 and 18 these cannot form a triangle
8 0
3 years ago
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