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Nadusha1986 [10]
3 years ago
13

A number is 42,300 when multiplied by 10. find the product of this number and 500

Mathematics
1 answer:
brilliants [131]3 years ago
8 0
The answer is 2,115,000

I hope I help you
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Jeremy walked 6/8 of the way to school and ran the rest of the way. What fraction in simplest form shows the part of the way tha
Leno4ka [110]
Hi there!

If Jeremy walked 6/8 of the way to school and ran the rest we know that Jeremy ran 2/8 of the way. We can simplify this further to get to our simplest form.

6/8 ---> 3/4 Simplified.

So your answer is Jeremy walked 3/4 of the way.
6 0
3 years ago
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On the first day of an experiment, a scientist counts 31 bacteria. On the eighth day of the experiment, the count is 310,000 bac
MAVERICK [17]
It’s b 10000 because if you multiply 31 times 10000 it 310,000
8 0
8 months ago
PLEASE SOMEONE HELP ME
kow [346]

Answer:

1/5 is not greater than 2/7 because 1/5 = 7/35 and 2/7 = 10/35.

7 0
2 years ago
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Ricardo spends 8/9 hr. reading the paper. He spends 1/4 of the time reading world news and splits the remaining time equally bet
lapo4ka [179]
Total time spent reading is = 8/9 hour

He spends 1/4 of the time reading world news. That is =  1/4 * 8/9 =  2/9 hour

Splits the remaining time equally.  Remaining time =  8/9 - 2/9 =  6/9

Splitting it equally =  6/9  divided by 2 =  6/9  * 1/2 =  3/9  = 1/3

Time spent reading comic is = 1/3 hour

I hope this helps.
5 0
3 years ago
Solve the inequality |* +31 &lt; |2x + 1.<br> |x+3|&lt;|2x+1|
Kisachek [45]

Answer:

Step-by-step explanation:

Here are the steps to follow when solving absolute value inequalities:

Isolate the absolute value expression on the left side of the inequality.

If the number on the other side of the inequality sign is negative, your equation either has no solution or all real numbers as solutions.

If your problem has a greater than sign (your problem now says that an absolute value is greater than a number), then set up an "or" compound inequality that looks like this:

(quantity inside absolute value) < -(number on other side)

OR

(quantity inside absolute value) > (number on other side)

The same setup is used for a ³ sign.

If your absolute value is less than a number, then set up a three-part compound inequality that looks like this:

-(number on other side) < (quantity inside absolute value) < (number on other side)

The same setup is used for a £ sign

7 0
3 years ago
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