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pogonyaev
3 years ago
14

Find the product -7(-a2)(-b3)

Mathematics
1 answer:
vlada-n [284]3 years ago
7 0
-7(-a^2)(-b^3)=\boxed{-7a^2b^3}
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A circular dinner plate has a radius of 20 centimeters. Find a. the circumference of the plate and b. the area of the plate. Use
gayaneshka [121]

Answer:

The area is approximately 1256.64         The circumference is approximately 125.66

Step-by-step explanation:

This is because to find the area of a circle you square the radius and multiply by Pi. To find circumference, you can multiply the Diameter (twice radius) by Pi.

7 0
3 years ago
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Please help me this is a post test!
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3 years ago
How many extraneous solutions does the equation below have?
FrozenT [24]

<u>Answer</u>

0


<u>Explanation</u>

(2m)/(2m+3)-(2m)/(2m-3)=1

Simplifying the left hand first

(2m)/(2m+3)-(2m)/(2m-3) = {2m(2m-3) - 2m(2m+3)}/(4m²-9)

                                        (4m²-6m-4m²-6m)/(4m²-9)

                                         = (-12m) / (4m²-9)

Now this equet to 1

(-12m) / (4m²-9) = 1

-12m =  4m²-9

4m²+ 12m -9 =0 ⇒⇒⇒ This is a quadratic equation that has 2 real solutions.

4m²+ 12m -9 =0

m² + 3m + (3/2)²= 9/4 + 9/4

(m + 3/2)² = 18/4

m = √18/2 - 3/2                or m = -√18/2 - 3/2

    = 0.621                                       = -3.621

So we can say that the equation has NO extraneous solutions.

Answer = 0

8 0
3 years ago
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What is the answer to this algebra 1 answer : 6&gt; 4-2×&lt;4
Artist 52 [7]
6>4-2x<4

so therefor (4x-2) must be less than 6 and less than 4
it must be
6>4-2x and 4<4-2x
find the intersection

6>4-2x
add 2x to both sides
6+2x>4
subtract 6
2x>-2
divide by 2
x>-1



4>4-2x
add 2x
4+2x>4
subtract 4
2x>0
x>0




so we have
x>0
and x>-1
the range of x>-1 includes most of x>0 so the answer is
x>-1

6 0
3 years ago
The polynomial of degree 3 , P ( x ) , has a root of multiplicity 2 at x = 5 and a root of multiplicity 1 at x = − 4 . The y -in
goblinko [34]

Answer:

f kff

8dyd6f

8tc7ivcucuvvicuugovihkviivusxxsgivkv

dudic. xttcuccu vu Ucguccxigvùc. ,cuvuvv, ,,ycycucoUcguccucuiciviccuib

7gycuffguxh0h8h8bibihih and his colleagues are now on 8to 999as in 9999o

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