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Y_Kistochka [10]
3 years ago
13

Please help I'm in a rush, will give brainliest for a good answer!

Mathematics
1 answer:
elena-s [515]3 years ago
4 0

Answer:

The value of x is 4.

Step-by-step explanation:

From the image uploaded, line BC is parallel to line AD and 15 is the mid-segment.

The mid-segment of a trapezoid is calculated as;

15 = \frac{|BC| \ + \ |AD|}{2} \\\\15 = \frac{2x \ + \ (3x\ +\ 10)}{2} \\\\15 = \frac{2x \ + \ 3x \ + \ 10}{2} \\\\15 = \frac{5x \ + \ 10}{2} \\\\5x \ + \ 10 = 2(15)\\\\5x \ + \ 10 = 30\\\\5x = 30 -10\\\\5x = 20\\\\x = \frac{20}{5} \\\\x = 4

Thus, the value of x is 4.

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Roundup Racquets restrings tennis racquets for $22. If the store restrings 20 racquets each month, what is the monthly revenue f
ser-zykov [4K]

Answer:

The revenue would be $ 440

Step-by-step explanation:

Consider the correct complete question is,

"Roundup Rackets restrings a tennis racket for $22. If the store restrings 20 rackets each month, what is the monthly revenue from restringing rackets."

Thus,

The price for restrings each tennis racket = $ 22,

Number of rackets re stringed in a month = 20,

Hence, the monthly revenue = price of restrings each tennis racket × number of rackets re stringed

= 22 × 20

= $ 440

7 0
3 years ago
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sattari [20]

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6 0
3 years ago
Prove the divisibility of the following numbers:
Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}

(B)

72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}

In this case, it is easier to also factor the divisor to primes:

72^{63}=2^{189}\cdot 3^{126}

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}

6 0
3 years ago
The point (–7, –3) is located in which quadrant?
andrezito [222]
Quadrant 3 is the answer
7 0
3 years ago
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DanielleElmas [232]

Answer:

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