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Westkost [7]
3 years ago
14

The point (–7, –3) is located in which quadrant?

Mathematics
2 answers:
andrezito [222]3 years ago
7 0
Quadrant 3 is the answer
maks197457 [2]3 years ago
6 0
The answer is Quadrant III

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Can anyone help with my math problems because I need help and you need to be quick. I will mark brainliest.
LiRa [457]
What are the math problems?
3 0
3 years ago
3. What is the slope of the line that contains the
dlinn [17]

Answer:

I think the answer would be -1/2 or D.

Step-by-step explanation:

Use this formula for calculating slope : y2-y1 / x2 - x1                                                            

1. label the pairs, 1 and 2

(-6, 1)  - ( x1, y1 )          or        (4,-4) - (x1, y1)

(4,-4) - ( x2, y2)                      (-6,1) - (x2, y2)  

(the order does not matter)

2. Than plug in your numbers

y2-y1 / x2 -x1                 y2-y1 / x2 -x1

-4 - 1 / 4 - (-6)        or        1 - (-4) / -6 - 4

= -5/10 or -1/2               = - 5/-10 or -1/2

im only in eight grade so i did my best explaining , and this hope it helps :)

7 0
3 years ago
Given that x square + 5 x + c is a perfect square find the value of C ​
lawyer [7]

Answer:

c = \frac{25}{4}

Step-by-step explanation:

To make a perfect square

add ( half the coefficient of the x- term )² to x² + 5x

x² + 5x + (\frac{5}{2} )²

= x² + 5x + \frac{25}{4}

= (x + \frac{5}{2} )² ← a perfect square

5 0
3 years ago
-4+x= -11 please answer it
Slav-nsk [51]

Answer:

x=-7

Step-by-step explanation:

add 4 to both sides. leaving you with x=-7

8 0
3 years ago
Read 2 more answers
On a particular production line,the likelihood that a light bulb is defective is 5%. Ten light bulbs are randomly selected. What
KengaRu [80]

Answer:

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

Step-by-step explanation:

Consider the provided information,

Let X is the number of defective bulbs.

Ten light bulbs are randomly selected.

The likelihood that a light bulb is defective is 5%.

Therefore sample size is = n = 10

Probability of a defective bulb = p = 0.05.

Therefore, q = 1 - p = 1 - 0.05 = 0.95

Mean of binomial random variable: \mu=np

Therefore, \mu=10(0.05)=0.5

Variance of binomial random variable: \sigma^2=npq

Therefore, \sigma^2=10(0.05)(0.95)=0.475

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

5 0
2 years ago
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