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lana66690 [7]
3 years ago
11

This table represents a proportional relationship. Use the table to identify the constant of proportionality between the ratio o

f the number of laps to the number of swimmers.
The constant of proportionality is ___​

Mathematics
2 answers:
sashaice [31]3 years ago
7 0

Answer:

The answer that you're looking for is <u>12</u>

Step-by-step explanation:

vodomira [7]3 years ago
6 0

Answer:

12

Step-by-step explanation:

We all hate school

You might be interested in
How do I️ solve this
Grace [21]
While you didn't post the instructions for this problem, I can safely assume that you're supposed to factor 8x^2 - 8x - 30.

First, note that all of these terms can be divided by 2:

8x^2 - 8x - 30 = 2(4x^2 - 4x - 15)

Inside the parentheses is a quadratic equation which can't be reduced further.  There are a good number of methods that you could use to solve this quadratic:

graphing, completing the square, factoring, quadratic formula, and so on.

I note that the first and last coefficients are 4 and 15.

Thus, possible roots are:

numerator           1, 3, 5, 15, -1, -3, -5, -15
------------------ = -----------------------------------
denominator        1, 2, 4, -1, -2, -4

For example, one root might be -5/2 (-5 from the numerator and 2 from the denominator).

Let's check whether -5/2 is actually a soluion, using synthetic div:

            ___________________
  -5/2   /   4        -4      -15
                        -10      7/2
                  __________________
               4       -14      Remainder is NOT zero, so -5/2 is not a root.

Lots of possibilities here.

Thus, I'm going to resort to the good old Quadratic Formula to determine the 
factors of 4x^2 -4x - 15:

a=4, b= -4 and c = -15

Then the the roots are:

         4 plus or minus sqrt(16-4(4)(-15)
x = ------------------------------------------------
                               8
        4 plus or minus sqrt(256)        4 plus or minus 16
   = ------------------------------------- = -------------------------------
                                8                                 8

    = 20/8 and -12/8, or 5/2 and -3/2

Thus, in factored form the polynomial is 8(x-5/2)(x+3/2)
6 0
3 years ago
What is 2 and 1/5 as a improper fraction
Degger [83]
2x5+1 =11/5 twjsjdjehd
7 0
3 years ago
Read 2 more answers
The opponents of soccer team A are of two types: either they are a class 1 or a class 2 team. The number of goals team A scores
NikAS [45]

Answer:

a) The expected number of goals team A will score is 5.1

b) The probability that team A will score a total of 5 goals is 0.1147

Step-by-step explanation:

Let X be the amount of goals scored by team A in both matches. Let X1 and X2 be the total amount of goals team A scores in match 1 and 2 respectively, then X = X1+X2, and also

a)

E(X) = E(X1+X2) = E(X1)+E(X2) = 0.6*2+0.4*3 + 0.3*2+0.7*3 = 5.1

b) In order for X to be equal to 5 we have 5 possibilities

- X1 is 0 and X2 is 5

- X1 is 1 and X2 is 4

- X1 is 2 and X2 is 3

- X1 is 3 and X2 is 2

- X1 is 4 and X2 is 1

- X1 is 5 and X2 is 0

Let T1 be a poisson distribution with mean λ = 2, then

P(T1=0) = e^{-2}

P(T1=1) = 2 * e^{-2}

P(T1=2) = 2 * e^{-2}

P(T1=3) = \frac{4}{3} \, e^{-2}

P(T1=4) = \frac{2}{3}\, e^{-2}

P(T1=5) = \frac{4}{15}\,e^{-2}

Lets do the same with a Poisson distribution T2 with mean λ = 3

P(T2=0) = e^{-3}

P(T2=1) = 3 \, e^{-3}\\P(T2=2) = \frac{9}{2} \, e^{-3}\\P(T2=3) = \frac{9}{2} \, e^{-3}\\P(T2=4) = \frac{27}{8} \, e^{-3}\\P(T2=5) = \frac{81}{40} \, e^{-3}

Now, we are ready to compute the probability that X is equal to 5.

P(X1 = 0, X2 = 5) = (0.6* e^{-2} + 0.4*e^{-3}) * (0.3*\frac{4}{15}e^{-2}  + 0.7*\frac{81}{40} e^{-3}) = 0.00823\\P(X1 = 1, X2 = 4) = (0.6* 2e^{-2} + 0.4*3 e^{-3}) * (0.3*\frac{2}{3}e^{-2}  + 0.7*\frac{27}{8} e^{-3}) = 0.03214\\P(X1 = 2, X2 = 3) = (0.6* 2e^{-2} + 0.4*\frac{9}{2}e^{-3}) * (0.3*\frac{4}{3}e^{-2}  + 0.7*\frac{9}{2} e^{-3}) = 0.05317\\P(X1 = 3, X2 = 2) = (0.6* \frac{4}{3}e^{-2} + 0.4*\frac{9}{2}*e^{-3}) * (0.3*2e^{-2}  + 0.7*\frac{9}{2} e^{-3}) = 0.0471

P(X1 = 4, X2 = 1) = (0.6* \frac{2}{3}e^{-2} + 0.4*\frac{27}{8}e^{-3}) * (0.3*2e^{-2}  + 0.7*3e^{-3}) = 0.0225\\P(X1 = 5, X2 = 0) = (0.6* \frac{4}{15}e^{-2} + 0.4*\frac{81}{40}e^{-3}) * (0.3*e^{-2}  + 0.7*e^{-3}) = 0.0047

We can conclude that

P(X = 5) = 0.00823+0.03214+0.05317+0.0471+0.0225+0.0047 = 0.1147

The probability that team A will score a total of 5 goals is 0.1147

7 0
3 years ago
Need help quickkkkkkkkkkk​
goldfiish [28.3K]

Answer:

C. The proof is done.

Step-by-step explanation:

i could be wrong but if i remember correctly QED stands for Quod Erat Demonstrandum

4 0
3 years ago
Read 2 more answers
Translate into an algebraic expression: n−1 increased by 110%
lorasvet [3.4K]

Answer:

Part 1) The algebraic expression is equal to 1.10(n-1)  or 1.10n-1.10

Part 2) The algebraic expression is equal to \frac{1.10}{n}

Step-by-step explanation:

Part 1) we have (n-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

1.10(n-1)

Distributed

1.10n-1.10

Part 2) we have n^(-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

n^{-1}=\frac{1}{n}

so

1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}

4 0
4 years ago
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