While you didn't post the instructions for this problem, I can safely assume that you're supposed to factor 8x^2 - 8x - 30.
First, note that all of these terms can be divided by 2:
8x^2 - 8x - 30 = 2(4x^2 - 4x - 15)
Inside the parentheses is a quadratic equation which can't be reduced further. There are a good number of methods that you could use to solve this quadratic:
graphing, completing the square, factoring, quadratic formula, and so on.
I note that the first and last coefficients are 4 and 15.
Thus, possible roots are:
numerator 1, 3, 5, 15, -1, -3, -5, -15
------------------ = -----------------------------------
denominator 1, 2, 4, -1, -2, -4
For example, one root might be -5/2 (-5 from the numerator and 2 from the denominator).
Let's check whether -5/2 is actually a soluion, using synthetic div:
___________________
-5/2 / 4 -4 -15
-10 7/2
__________________
4 -14 Remainder is NOT zero, so -5/2 is not a root.
Lots of possibilities here.
Thus, I'm going to resort to the good old Quadratic Formula to determine the
factors of 4x^2 -4x - 15:
a=4, b= -4 and c = -15
Then the the roots are:
4 plus or minus sqrt(16-4(4)(-15)
x = ------------------------------------------------
8
4 plus or minus sqrt(256) 4 plus or minus 16
= ------------------------------------- = -------------------------------
8 8
= 20/8 and -12/8, or 5/2 and -3/2
Thus, in factored form the polynomial is 8(x-5/2)(x+3/2)
Answer:
a) The expected number of goals team A will score is 5.1
b) The probability that team A will score a total of 5 goals is 0.1147
Step-by-step explanation:
Let X be the amount of goals scored by team A in both matches. Let X1 and X2 be the total amount of goals team A scores in match 1 and 2 respectively, then X = X1+X2, and also
a)
E(X) = E(X1+X2) = E(X1)+E(X2) = 0.6*2+0.4*3 + 0.3*2+0.7*3 = 5.1
b) In order for X to be equal to 5 we have 5 possibilities
- X1 is 0 and X2 is 5
- X1 is 1 and X2 is 4
- X1 is 2 and X2 is 3
- X1 is 3 and X2 is 2
- X1 is 4 and X2 is 1
- X1 is 5 and X2 is 0
Let T1 be a poisson distribution with mean λ = 2, then






Lets do the same with a Poisson distribution T2 with mean λ = 3


Now, we are ready to compute the probability that X is equal to 5.


We can conclude that
P(X = 5) = 0.00823+0.03214+0.05317+0.0471+0.0225+0.0047 = 0.1147
The probability that team A will score a total of 5 goals is 0.1147
Answer:
C. The proof is done.
Step-by-step explanation:
i could be wrong but if i remember correctly QED stands for Quod Erat Demonstrandum
Answer:
Part 1) The algebraic expression is equal to
or 
Part 2) The algebraic expression is equal to 
Step-by-step explanation:
Part 1) we have (n-1) increased by 110%
110%=110/100=1.10
so
The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

Distributed

Part 2) we have n^(-1) increased by 110%
110%=110/100=1.10
so
The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)
Remember that

so
