The answer would be 11.
I hope that this will help somebody :)
Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula

a) To find the initial amount of this substance
At t=0, we get


We know that e^0=1 ( anything to the power zero is 1)
we get,

The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,


Taking natural logarithm on both sides we get,







Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,




The amount of substance will be present around in 2500 years is 0.000585 grams
the answer should be letter A
the difference of 3.4 and 1.25 = 2.15
Now you know that there will be 2 whole blocks and .15 of a block
.15 is equal to 3/20 which is equal to 15/100.
So you will have 2 whole blocks and 15/100 of a blocks. So the answer is A
Answer:
Option D.
3 equations with 3 variables
Step-by-step explanation:
The coordinates of a point in space must necessarily have 3 components. One to describe the distance on the x axis, another to describe the distance on the y axis to the point, and a third to describe the distance on the z axis.
If we have three variables, then 3 equations are needed to solve the system. With less than 3 equations it would be impossible to solver the system.
Therefore the correct answer is option D.
3 equations with 3 variables
Answer:
Step-by-step explanation:
25