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leva [86]
3 years ago
14

1200/180 = (can someone please help me I'm desperate)

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0

Using a calculator, 1200/180 = 6.67 approximately

If you use long division, then you'll get what you see in the diagram below

The 6's go on forever after the decimal point, but if you round to two decimal places, then you'll get that approximate value of 6.67

---------------

If you want a remainder, then 1200/180 = 6 remainder 120

You can think of it like you having 1200 cookies and 180 friends. Each friend will get 6 whole cookies and there will be 120 left over as the remainder.

You might be interested in
Data from the Centers for Medicare and Medicaid Services indicates that the annual per capita out-of-pocket expenses for health
Talja [164]

Answer:

During the year 2021.

Step-by-step explanation:

As we have a function that defines the annual per capita out-of-pocket expenses for health care, we can work with it.

Knowing that, <u>we clear x</u> (<em>this is the number of years past the year 2000, so it will contain our desired information</em>).

y=39.6x+543\Leftrightarrow x=\frac{y-543}{39.6}

Now, as we want to know when are the per capita out-of-pocket expenses for health care predicted to be $1400, and <em>this total is our variable y</em>, then

x=\frac{1400-543}{39.6}\approx 21.6

Finally, we know that <u>x is the number of years past the year 2000</u>, so the answer is that during the year 2021, <em>the per capita out-of-pocket expenses for health care are predicted to be $1400</em>.

3 0
3 years ago
Half of the tuna sandwich were on white bread. 25% of the ham sandwiches sold were on brown bread.
fgiga [73]

Answer:

The frequency table is shown below.

Step-by-step explanation:

(i) Half of the tuna sandwich were on white bread = 21

On brown bread, tuna = 42 - 21 = 21

(ii) 25% of the ham sandwiches sold were on brown bread.

= 25% (32) = 8

On white bread, 32 - 8 = 24

Frequency table:

                     Tuna             Cheese          Ham         Total

Brown             21                     11                    8                40

White              21                     15                  24               60

Total                42                     26                 32              100

6 0
3 years ago
$80 at 12%for 2years
Ivan

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>y</em><em>o</em><em>u</em><em>.</em><em>.</em>

8 0
3 years ago
I am having trouble with this relative minimum of this equation.<br>​
Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach.  You have to let me know if you want this done another way.

Here are some rules I'm going to use:

(f+g)'=f'+g'       (Sum rule)

(cf)'=c(f)'          (Constant multiple rule)

(x^n)'=nx^{n-1} (Power rule)

(c)'=0               (Constant rule)

(x)'=1                (Slope of y=x is 1)

y=4x^3+13x^2-12x-56

y'=(4x^3+13x^2-12x-56)'

y'=(4x^3)'+(13x^2)'-(12x)'-(56)'

y'=4(x^3)'+13(x^2)'-12(x)'-0

y'=4(3x^2)+13(2x^1)-12(1)

y'=12x^2+26x-12

Now we set y' equal to 0 and solve for the critical numbers.

12x^2+26x-12=0

Divide both sides by 2:

6x^2+13x-6=0

Compaer 6x^2+13x-6=0 to ax^2+bx+c=0 to determine the values for a=6,b=13,c=-6.

a=6

b=13

c=-6

We are going to use the quadratic formula to solve for our critical numbers, x.

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}

x=\frac{-13 \pm \sqrt{169+144}}{12}

x=\frac{-13 \pm \sqrt{313}}{12}

Let's separate the choices:

x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}

Let's approximate both of these:

x=0.3909838 \text{ or } -2.5576505.

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

f(x)=4x^3+13x^2-12x-56

f'(x)=12x^2+26x-12

f''(x)=24x+26

So if f''(a) is positive then we have a minimum at x=a.

If f''(a) is negative then we have a maximum at x=a.

Rounding to nearest tenths here:  x=-2.6 and x=.4

Let's see what f'' gives us at both of these x's.

24(-2.6)+25

-37.5  

So we have a maximum at x=-2.6.

24(.4)+25

9.6+25

34.6

So we have a minimum at x=.4.

Now let's find the corresponding y-value for our relative minimum point since that would complete your question.

We are going to use the equation that relates x and y.

I'm going to use 0.3909838 instead of .4 just so we can be closer to the correct y value.

y=4(0.3909838)^3+13(0.3909838)^2-12(0.3909838)-56

I'm shoving this into a calculator:

y=-58.4654411

So the approximate relative minimum is (0.4,-58.5).

If you graph y=4x^3+13x^2-12x-56 you should see the graph taking a dip at this point.

3 0
3 years ago
241.78 divided by (-3.85)
koban [17]

Answer:

-62.8 is the answer .......................

3 0
2 years ago
Read 2 more answers
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