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3 years ago

8

If someone can just answer the first question that would be so helpful plzzz

1 answer:

slavikrds [6]3 years ago

5 0

Answer:

I'm guessing that when you graph it, the graph changes direction when it's not on the x-axis. the "real zeros" of a graph are the ones that go through the x-axis and then imaginary ones are the ones that don't.

Step-by-step explanation:

You might be interested in

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

3 years ago

When Robert got a puppy from the shelter, it weigh 11 pounds. The puppy gained 40% of its original weight in the first month tha

Iteru [2.4K]

The puppy weighs 15.4 pounds, 40% of 11 is 4.4 so add that to the wight and its 15.4

3 0

3 years ago

Pete has 3 dollars less than what Linda has. If together has 81 dollars how much does each person have?

Makovka662 [10]

Answer:

Pete: 39, Linda: 42

Step-by-step explanation:

Suppose Pete has x dollars. If he has 3 dollars less than Linda, then Linda has 3+x dollars. Together, they have 81 dollars:

x+3+x=81

2x+3=81

2x=78

x=39

Since Pete has x dollars, and x=39, he has $39.

Linda has 3+x, which is 39+3 = $42

<em>I hope this helps! :)</em>

8 0

3 years ago

line segment AB has endpoints A (7.5,4.2) and B (2.3,5.4). Find the coordinates of the point that divides the line segment direc

Marrrta [24]

9514 1404 393

Answer:

(6.2, 4.5)

Step-by-step explanation:

We want, for some point P, ...

(P -A) / (B -P) = 1 / 3

3(P -A) = (B - P) . . . . . multiply by 3

4P = B +3A . . . . . . . . add P+3A

P = (B +3A)/4 . . . . . . .divide by 4

Filling in the coordinate values, we can find P to be ...

P = ((2.3, 5.4) +3(7.5, 4.2))/4 = (2.3+22.5, 5.4+12.6)/4

P = (6.2, 4.5)

5 0

3 years ago

Please help!!! ILL GIVE U BRAINLIEST.

Viktor [21]

Answer:

f(x) is translated by 4 units left.

Step-by-step explanation:

did it help ?

well, hope it helps !

6 0

3 years ago