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3 years ago

Sum of 2 numbers is 42, and their difference is 8. What are the numbers?

Mathematics

2 answers:

Tems11 [23]3 years ago

8 0

Answer:

25 , 17

Step-by-step explanation:

Let the unknown two numbers be x & y.

According to the question,

Sum of 2 numbers is 42.

x + y = 42 ⇒ ( 1 )

Their difference is 8.

x - y = 8 ⇒ ( 2 )

First let us find the value of x.

( 1 ) + ( 2 )

x + y + x - y = 42 + 8

2x = 50

Divide both sides by 2.

x = 25

And now let us find the value of y.

x + y = 42

25 + y = 42

y = 42 - 25

y = 17

Therefore, the two numbers are 25 , 17

Hope this helps you :-)

Let me know if you have any other questions :-)

Verdich [7]3 years ago

5 0

Answer:

$let \: the \: numbers \: be \: x \: and \: y \\ x + y = 42....(1) \\ x - y = 8....(2) \\ now \\ x + y = 42 \\ x = 42 - y \\ again \\ x - y = 8 \\ x = 8 + y \\ putting \: the \: value \: of(x) \\ \\ 42 - y = 8 + y \\ 2y = 42 - 8 \\ 2y = 34 \\ y = 34 \div 2 \\ y = 17 \\ putting \: the \: value \: in \: equation \: (1) \\ x + y = 42 \\ x = 42 - 17 \\ x = 25$

x=25 and y=17

hope it helps.

stay safe healthy and happy.

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Answer:

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Step-by-step explanation:

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3 years ago

4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10

Andrew [12]

Given the function f(x);

$f(x)=-4x^2+4x-1$

Evaluating the function f(x+h);

$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

So;

$f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1$

Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

simplifying further;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}$

Therefore, we have;

$undefined$

7 0

1 year ago

rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4

OleMash [197]

Answer:

The standard form is 8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of y⁴ is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.

The form ax⁵ + b x⁴ + c x³ +d x² +ex +f is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial

now Given polynomial is 2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

Conclusion:-

The degree of given polynomial is '5'

The co-efficient of y⁴ is '-17'

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3 years ago

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Answer:

I'll answer if u make my Answer Brainliest!!! <33333333

I know the answer btw!

Step-by-step explanation:

Also HII <3

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3 years ago

Sum of 2 numbers is 42, and their difference is 8. What are the numbers?​

Sum of 2 numbers is 42, and their difference is 8. What are the numbers?