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3 years ago

Sum of 2 numbers is 42, and their difference is 8. What are the numbers?

Mathematics

2 answers:

Tems11 [23]3 years ago

8 0

Answer:

25 , 17

Step-by-step explanation:

Let the unknown two numbers be x & y.

According to the question,

Sum of 2 numbers is 42.

x + y = 42 ⇒ ( 1 )

Their difference is 8.

x - y = 8 ⇒ ( 2 )

First let us find the value of x.

( 1 ) + ( 2 )

x + y + x - y = 42 + 8

2x = 50

Divide both sides by 2.

x = 25

And now let us find the value of y.

x + y = 42

25 + y = 42

y = 42 - 25

y = 17

Therefore, the two numbers are 25 , 17

Hope this helps you :-)

Let me know if you have any other questions :-)

Verdich [7]3 years ago

5 0

Answer:

$let \: the \: numbers \: be \: x \: and \: y \\ x + y = 42....(1) \\ x - y = 8....(2) \\ now \\ x + y = 42 \\ x = 42 - y \\ again \\ x - y = 8 \\ x = 8 + y \\ putting \: the \: value \: of(x) \\ \\ 42 - y = 8 + y \\ 2y = 42 - 8 \\ 2y = 34 \\ y = 34 \div 2 \\ y = 17 \\ putting \: the \: value \: in \: equation \: (1) \\ x + y = 42 \\ x = 42 - 17 \\ x = 25$

x=25 and y=17

hope it helps.

stay safe healthy and happy.

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4 years ago

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3 years ago

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Simplify (7x+42)/(x^2+13x+42)

Colt1911 [192]

$\frac{7x+42}{x^2+13x+42}= \frac{7(x+6)}{x^2+7x+6x+42}= \frac{7(x+6)}{x(x+7)+6(x+7)}= \frac{7(x+6)}{(x+6)(x+7)}= \frac{7}{x+7}$

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3 years ago

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Please help me out :((

olga_2 [115]

Answer:

1) 5*x + 6 = 2 + 3*x

5*x - 3*x = 2 - 6

(5 - 3)*x = -4

2*x = - 4

x = -4/2 = -2

x = -2

We have only one solution.

2) 2*(6 - 2*y) = -1*(4*y - 9)

12 - 4*y = -4*y + 9

12 - 9 = -4*y + 4*y = 0

3 = 0

This is absurd, so this equation has no solution.

3) 2*z - 6 = 2*(z + 2) - 10

2*z - 6 = 2*z + 4 - 10

2*z - 6 = 2*z - 6

Here we have the exact same thing on both sides of the equation, then we have infinite solutions, this happens because z can take any value, and the equation will be true always.

4) We want to have no solutions, so we need to end with something like:

1 = 6

so, we start with:

5*x + 1 = 5*x + A

We want to find the value of A.

First, we can subtract 5*x in both sides, so we get:

1 = A

Now we just need to take A different than 1, for example, if A = 2, then:

1 = 2

In this case the equation has no solutions, then we have:

5*x + 1 = 5*x + 2

5) We want to have one solution:

3*x - 3 = A*x + 11

We want to end with something like x = k

Let's solve the equation for x:

3*x - 3 = A*x + 11

3*x - A*x = 11 + 3

(3 - A)*x = 14

if we take A = 2, then:

(3 - 2)*x = 14

x = 14

So this equation has only one solution, the equation is:

3*x - 3 = 2*x + 11

6) We want to have infinitely many solutions, then we need to have the same thing on both sides, then we need to have an equation like:

8*x - 7 = 8*x - 7

6 0

3 years ago

How many different integers between $100$ and $500$ are multiples of either $6,$ $8,$ or both?

nirvana33 [79]

We need to find the number of integers between 100 and 500 that can be divided by 6, 8, or both. Now, to do this, we must as to how many are divisible by 6 and how many are multiples of 8.

The closest number to 100 that is divisible by 6 is 102. 498 is the multiple of 6 closest to 500. To find the number of multiple of 6 from 102 to 498, we have

$n = \frac{498-102}{6} + 1$
$n = 67$

We can use the same approach, to find the number of integers that are divisible by 8 between 100 and 500.

$n = \frac{496-104}{8} + 1$
$n = 50$

That means there are 67 integers that are divisible by 6 and 50 integers divisible by 8. Remember that 6 and 8 share a common multiple of 24. That means the numbers 24, 48, 72, 96, etc are included in both lists. As shown below, there are 16 numbers that are multiples of 24.

$n = \frac{480-120}{24} + 1$
$n = 16$

Since we counted them twice, we subtract the number of integers that are divisible by 24 and have a final total of 67 + 50 - 16 = 101. Hence there are 101 integers that are divisible by 6, 8, or both.

Answer: 101

8 0

3 years ago

Sum of 2 numbers is 42, and their difference is 8. What are the numbers?​

Sum of 2 numbers is 42, and their difference is 8. What are the numbers?