−40+10a= \,\,-70 −70
1 answer:
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The picture in the attached figure
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer is
m∠1 is 56.5°
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer is
m∠1 is 56.5°