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olga_2 [115]
3 years ago
10

Let f(x)=3x+1 and g(x)=2x2−1 Find f(g(2)) 10 22 97 28

Mathematics
1 answer:
kupik [55]3 years ago
6 0

Answer:

f(g(2)) = 22

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Composition of functions

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x + 1

g(x) = 2x² - 1

<u>Step 2: Find g(2)</u>

  1. Substitute:                    g(2) = 2(2)² - 1
  2. Evaluate:                       g(2) = 2(4) - 1
  3. Multiply:                        g(2) = 8 - 1
  4. Subtract:                       g(2) = 7

<u>Step 3: Find f(g(2))</u>

  1. Define:                    g(2) = 7
  2. Rewrite:                   f(7)
  3. Substitute:               f(7) = 3(7) + 1
  4. Multiply:                   f(7) = 21 + 1
  5. Add:                         f(7) = 22

And we have our final answer!

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Explain when you must write the number 1, and when you do not need to.
stepan [7]

Answer:

The number 1 is not necessary when expressing powers of one. For example, you needn't write "5" as 5^{1}.

Step-by-step explanation:

7 0
3 years ago
A 12-foot ladder leans against the wall; the base of the ladder is 2 feet away from the wall.To the nearest tenth of a foot, how
ludmilkaskok [199]
<h3>The ladder will reach a height of 11.8 feet up the wall</h3>

<em><u>Solution:</u></em>

The ladder, wall and base of the ladder from wall forms a right angled triangle

Length of ladder forms the hypotenuse

Length of ladder = 12 foot

base of the ladder from wall = 2 feet

<em><u>To find: height of wall</u></em>

By pythagoras theorem.

c^2 = a^2+b^2

Where,

"c" is the Length of ladder

"a" is the base of the ladder from wall

"b" is the height of wall

Substituting the values,

12^2 = 2^2+b^2\\\\144 = 4 + b^2\\\\b^2 = 140\\\\b = \pm 11.832 \\\\Ignore\ negative\ value\\\\b \approx 11.8

Thus, the ladder will reach a height of 11.8 feet on wall

4 0
3 years ago
How to find equation hyperbola with asymptotes, center and transverse?
lapo4ka [179]
The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate 
together they represent a point, which is the center
So (h,k) is (x,y)

The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola. 
6 0
3 years ago
Please help!
Sholpan [36]
The first one is correct because the angle on the opposite side is the same, and the second one is correct too because it's the same points.  So you can pick either or.
6 0
3 years ago
Read 2 more answers
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asambeis [7]

Option 4 is the answer.

50+30

=80

10(5+3)

= 10×8

=80

Hence, the correct option => 10(5+3)

Hope it helps!

7 0
3 years ago
Read 2 more answers
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