Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Answer:
4+12+8 = 24
Step-by-step explanation:
4+8=12 + 12 = 24 :)
Answer:
Step-by-step explanation:
Given
Equation:
Required
Determine the equation of Point: (5,4)
First, we need to determine the slope of
The general form of an equation is 
Where m represents the slope;
Hence; 
Since the equation and the point are parallel. then they have the same slope (m).
Next, is to determine the equation of the point, using the following formula:
Where
So, the equation becomes
Cross Multiply
Open Bracket
Make y the subject of formula
Hence, the equation is
The outer exponent is 4 so there will be 5 terms all together. By rules of exponents
C(4,0)(3^4)(2^0)(x^8)(y^0) + C(4,1)(3^3)(2^1)(x^6)(y^3) + C(4,2)(3^2)(2^2)(x^4)(y^6) + C(4,3)(3^1)(2^3)(x^2)(y^9) + C(4,4)(3^0)(2^4)(x^0)(y^12)
The coefficient of the 3rd term: C(4,2)(3^2)(2^2) = 6 x 9 x 4 = 216
Answer:
There should be 6 blue bags.
Step-by-step explanation:
