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3 years ago

Which is the best estimate of (-3/5)(17 5/8)

Mathematics

1 answer:

Marta_Voda [28]3 years ago

7 0

Solving $(-\frac{3}{5})(17\frac{5}{8})$ we get $-10\frac{23}{40}$

Step-by-step explanation:

Solve: $(-\frac{3}{5})(17\frac{5}{8})$

We need to multiply the two terms.

Solving:

$(-\frac{3}{5})(17\frac{5}{8})$

Converting\,\,mixed\,\,fraction\,\,into\,\,improper\,\,fraction:

$(-\frac{3}{5})(\frac{141}{8})$

Now multiplying numerator with numerator and denominator with denominator:

$-\frac{423}{40} \\-10\frac{23}{40}$

So, Solving $(-\frac{3}{5})(17\frac{5}{8})$ we get $-10\frac{23}{40}$

Keywords: Solving Fractions

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4 years ago

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You are baking brownies for your class. There are 28 total students in your class and you have baked 23 brownies. Right and solv

slavikrds [6]

Answer:

$x = 33$

Step-by-step explanation:

Given

$Students = 28$

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$Brownies = 2\ per\ student$

Required

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If:

$Brownies = 2\ per\ student$

and there are 28 students

Then:

$Total\ Brownies = 2 * 28$

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4 years ago

For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12

notsponge [240]

The binomial distribution is given by,
P(X=x) = $(^{n}C_{x})p^{x} q^{n-x}$
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = $(^{100}C_{x})(0.2)^{x} (0.8)^{100-x}$
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) = $(^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1}$ + $(^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3}$ + $(^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5}$ + $(^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7}$ + $(^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9}$ + $(^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11}$ + $(^{100}C_{12})(0.2)^{12} (0.8)^{100-12}$

Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.

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4 years ago