2 years ago

Solve for x in the equation x2 - 8x+41 - 0

Mathematics

1 answer:

Liula [17]2 years ago

7 0

Answer:

x= 4+5i

Step-by-step explanation:

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3/4(-10+2/5) please answer asap

Tju [1.3M]

Answer:

3/4(-10+2+2/5)

answer -5.7

Step-by-step explanation:

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2 years ago

What pair of factors of -45 has a<br> sum of 4?

damaskus [11]

Answer:

9 and -5

Step-by-step explanation:

9*-5=-45

9+-5=4

5 0

2 years ago

Read 2 more answers

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

2 years ago

I need help. once again. bahahaha

katrin [286]

Answer:

letters d. and e.

5 0

3 years ago

Claire takes private lacrosse lessons every 6 days and piano lessons every 4 days. In 60 days, how often will she have lacrosse

uranmaximum [27]

Multiples of 4: 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60
12 24 36 and 48 are the only common factors
so 4 days

7 0

2 years ago