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One number is seven less than four times the other number. The sum of the two numbers is 93. Find the numbers.

ivann1987 [24]

You can write the two equations x = 4y - 7 and x + y = 93; substitute the value of x into the other equation

(4y - 7) + y = 93; combine like terms

5y - 7 = 93; add 7 to both sides

5y = 100; divide both sides by 5

y = 20; substitute this value into the other equation

x + 20 = 93

x = 73

So the numbers are 20 and 73

6 0

3 years ago

Suppose a 50-foot ladder is leaning against a wall. Which statements about the base of the ladder are true?

Liula [17]

Answer and Step-by-step explanation:

These are the statements that make the question complete:

A. If the base is 24 feet from the wall, the ladder reaches 45 feet up the wall.

B. If the base is 30 feet from the wall, the ladder reaches 40 feet up the wall.

C. If the base is 27 feet from the wall, the ladder reaches 44 feet up the wall.

D. If the base is 14 feet from the wall, the ladder reaches 48 feet up the wall.

Since the ladder leans against a wall, a right angle triangle is formed. Since the ladder is now slant, then it's length becomes the hypothenuse.

The correct statements can be gotten through Pythagoras theorem which says:

A² + B² = C² where C is the hypothenuse and A and B are the other two sides.

Since the hypothenuse is 50, we can test each statement by taking the square of the two sides and add them up, if they are equal to 50² = 2500, then the statement is true.

A. 24² + 45² = 576 + 2025 = 2601 ≠ 2500, therefore it is false.

B. 30² + 40² = 900 + 1600 = 2500, therefore it is true.

C. 27² + 44² = 729 + 1936 = 2665 ≠ 2500, therefore it is false

D. 14² + 48² = 196 + 2304 = 2500, therefore it is true.

From here, statements B and D are true while the rest are all false.

7 0

3 years ago

URGENT!!!! WILL GIVE BRANLIEST !!! AT LEAST TAKE A LOOK!!!!!! Find cosP. A) COS=29/21 B) ) COS=21/29 C) ) COS=20/29

Rina8888 [55]

Answer:

C. cos 20/29

Step-by-step explanation:

Cosine is adjacent over hypotenuse, like SohCahToa. Therefore, 20 is the adjacent side and 29 is the hypotenuse (hypotenuse is always the longest side).

3 0

3 years ago

You sell and offer seven vegetable toppings in 4 meat toppings. The base of a price for pizza is $11. You charge $1.50 for each

Evgesh-ka [11]

The answer is a (19.25)

8 0

3 years ago

Read 2 more answers

Will Mark Brainiest!!! Simplify the following:

xz_007 [3.2K]

Answer:

1.B

2.A

3. B

Step-by-step explanation:

1. $\frac{x+5}{x^{2} + 6x +5 }$

We have the denominator of the fraction as following:

$x^{2} + 6x + 5 \\= x^{2} + (1 + 5)x + 5\\= x*x + 1x + 5x + 5*1\\= x ( x + 1) + 5(x + 1)\\= (x + 1) (x + 5)$

As the initial one is a fraction, so that its denominator has to be different from 0.

=> ( $x^{2} +6x+5$ ) ≠ 0

⇔ (x +1) (x +5) ≠ 0

⇔ (x + 1) ≠ 0; (x +5) ≠ 0

⇔ x ≠ -1; x ≠ -5

Replace it into the initial equation, we have:

$\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)}$

As (x+5) ≠ 0; we divide both numerator and denominator of the fraction by (x +5)

=> $\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)} = \frac{1}{x+1}$

So that $\frac{x+5}{x^{2} + 6x +5 } = \frac{1}{x+1}$ with x ≠ 1; x ≠ -5

So that the answer is B.

2. $\frac{(\frac{x^{2} -16 }{x-1} )}{x+4}$

As the initial one is a fraction, so that its denominator has to be different from 0

=> x + 4 ≠ 0

=> x ≠ -4

As $\frac{x^{2}-16 }{x-1}$ is also a fraction, so that its denominator (x-1) has to be different from 0

=> x - 1 ≠ 0

=> x ≠ 1

We have an equation: $x^{2} - y^{2} = (x - y ) (x+y)$

=> $x^{2} - 16 = x^{2} - 4^{2} = (x -4) (x +4)$

Replace it into the initial equation, we have:

$\frac{(\frac{x^{2} -16 }{x-1} )}{x+4} \\= \frac{x^{2} -16 }{x-1} . \frac{1}{x + 4}\\= \frac{(x-4)(x+4)}{x-1}. \frac{1}{x + 4}$

As (x + 4) ≠ 0 (proven above), we can divide both numerator and the denominator of the fraction by (x +4)

=> $\frac{(x-4)(x+4)}{x-1} .\frac{1}{x+4} =\frac{x-4}{x-1}$

So that the initial equation is equal to $\frac{x-4}{x-1}$ with x ≠-4; x ≠1

=> So that the correct answer is A

3. $\frac{x}{4x + x^{2} }$

As the initial one is a fraction, so that its denominator (4x + x^2) has to be different from 0

We have:

(4x + x^2) = 4x + x.x = x ( x + 4)

So that: (4x + x^2) ≠ 0 ⇔ x ( x + 4 ) ≠ 0

⇔ $\left \{ {{x\neq 0} \atop {(x+4)\neq0 }} \right.$ ⇔ $\left \{ {{x\neq 0} \atop {x \neq -4 }} \right.$

As (4x + x^2) = x ( x + 4) , we replace this into the initial fraction and have:

$\frac{x}{4x + x^{2} } = \frac{x}{x(x+4)}$

As x ≠ 0, we can divide both numerator and denominator of the fraction by x and have:

$\frac{x}{x(x+4)} =\frac{x/x}{x(x+4)/x} = \frac{1}{x+4}$

So that $\frac{x}{4x+x^{2} } = \frac{1}{x+4}$ with x ≠ 0; x ≠ -4

=> The correct answer is B

3 0

4 years ago