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serg [7]
3 years ago
7

Which of the following algorithmic efficiencies would be considered LEAST efficient?

Computers and Technology
2 answers:
frutty [35]3 years ago
7 0

Answer:

It is definitely exponential

Explanation:

Think of it from an input perspective. When an input is put in in a linear, constant and polynomial function, it remains constant. The one wildcard of these choices is exponential. Exponential will initially be efficient, but as the input increases it will jump wildely unlike the rest of the options. This is hands down the right answer! Good luck on the rest of the test!

max2010maxim [7]3 years ago
3 0

Answer: D. Exponential

Explanation:

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ale4655 [162]
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#include <iostream>
#include <math>

int main()
{
// example area
double area = 25;

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double diagonal = sqrt(pow(sqrt(area), 2) + pow(sqrt(area), 2));

return 0;
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Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

   int evekount = 0, odkount = 0;

   for(int i = 0; i<50;i++){

       cin>>numbers[i];

       if(numbers[i]%2==0){            evekount++;        }

       else{            odkount++;        }

   }

   cout<<"Even Count: "<<evekount<<endl;

   cout<<"Odd Count: "<<odkount<<endl;

   return 0;

}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

   int evekount = 0, odkount = 0;

This iterates from 1 to 50

   for(int i = 0; i<50;i++){

This gets input for the array

       cin>>numbers[i];

This checks for even

<em>        if(numbers[i]%2==0){            evekount++;        }</em>

This checks for odd

<em>        else{            odkount++;        }</em>

   }

This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

   cout<<"Odd Count: "<<odkount<<endl;

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