Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
-29664 is the correct answer. This mostly deals with the zeros and crossing them off
Answer:
Step-by-step explanation:
alright lets get started.
Please refer the diagram I have attached.
the runner traveled, six kilometers east.
Next, they turn to north and suppose they run x kilometers.
The starting and the ending points distance is 10 kilometers.
There will be a right triangle formed, we can find the value of x by using Pythagorean theorem.
Subtracting 36 from both sides
So, the runners travel 8 kilometers to the north. : answer
Hope it will help. :)
Another way to write this is:
x = 23y + 5
xy = 6732
Now plug in the first equation into the second:
(23y + 5)y = 6732
23y^2 + 5y - 6732 = 0
Either use quadratic equation or factor:
(y - 17)(23y + 396) = 0
y = 17 or -396/23
You know you can automatically eliminate the second y because it's negative and you need the two integers to multiply to a positive number (6732).
Plug y = 17 back into either equation (second might be easier):
17x = 6732
x = 396
