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poizon [28]
4 years ago
11

The probability that a car will have a flat tire while driving through a certain tunnel is 0.00005. Use the Poisson distribution

to approximate the probability that among 14,000 cars passing through
 this tunnel, exactly two will have a flat tire.
A.0.8783
B.0.1947
C. 0.1460
D.0.1217
Mathematics
1 answer:
timama [110]4 years ago
5 0

Answer: D. 0.1217

Step-by-step explanation:

Given : The probability that a car will have a flat tire while driving through a certain tunnel :p=0.00005.

n= 14000

Then, the mean number of cars will have a flat tire while driving through a certain tunnel = np

=14000\times0.00005=0.7

Poisson Distribution Formula : P(x)=\dfrac{e^{-\lambda} \lambda^x}{x!}

For x= 2

P(2)=\dfrac{e^{-0.7} (0.7)^2}{2!}=0.121663399429\approx0.1217

Hence, the required probability = 0.1217

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Solve the following system of equations graphically on the set of axes below. Y=-1/2x +1 and y=x-5
Goshia [24]

Answer:

-1/2x+1=x-5

x=4

y=-4/2+1

y=-2+1

y=-1

(x,y)=(4,-1)

7 0
3 years ago
Find f(-1) (inverse) if y=4x+2/3x-1 and x is not equal with 1/3
Setler [38]
Before we find f^{-1}, let's think for a minute about what f does, and what it means to find the inverse of a function. A function f essentially takes a value <em />x from the <em>domain</em> and maps it to another value <em />y in that function's <em>range</em> according to a set of rules. Here, those rules are defined by the formula

y= \frac{4x+2}{3x-1} , x \neq \frac{1}{3}

All the inverse does is <em>swap the domain and range of the function</em>. Now, instead of trying to map x to y, we're trying to find a set of rules that'll map y back to x. To find those rules, all we have to do is solve the above equation for x.

First, we'll multiply both sides of the equation by 3x-1 to get it out of the denominator:

(3x-1)y=( \frac{4x+2}{3x-1})(3x-1)

Cancelling on the right side and distributing on the left, we get:

3xy-y=4x+2

Next, we collect all of our x terms on one side, and all of our non-x terms on the other:

(3xy-y)+y=(4x+2)+y\\(3xy)-4x=(4x+2+y)-4x\\3xy-4x=2+y

Let's rearrange the right side and factor out an x on the left:

x(3y-4)=y+2

And finally, we divide both sides by 3y-4 to obtain our answer:

[x(3y-4)]/(3y-4)=(y+2)/(3y-4)\\\\x= \frac{y+2}{3y-4}

This equation gives us the "rules" for mapping any given y in the range back to an x in the domain. If we swap the domain and the range, we can define our function 

f^{-1}(x)= \frac{x+2}{3x-4}
7 0
4 years ago
The combined area of two squares is 45 square centimeters.each side of one square is twice as long as the side of the other .wha
serg [7]
Formula of square area
a = s²
thus, area of the first square could be written as s₁² and area of the second square could be written as s₂²

First, write an expression in the form of equation system
An expression for "The combined area of two squares is 45 square centimeters" is:
⇒ s₁² + s₂² = 45 <em>(first equation)</em>
An expression for "Each side of one square is twice as long as side of the other" is:
⇒ s₁ = 2s₂ <em>(second equation)</em>

Second, solve the equation system by substitution method.
⇒ We could substitute 2s₂ to s₁ (second equation) in the first equation in order to find the value of s₂
s₁² + s₂² = 45
(2s₂)² + s₂² = 45
(2²)(s₂)² + s₂² = 45
4s₂² + s₂² = 45
5s₂² = 45
s₂² = 45/5
s₂² = 9
s₂² = 3²
s₂ = 3

⇒ Substitute the value of s₂ to the second equation in order to find the value of s₁
s₁ = 2s₂
s₁ = 2(3)
s₁ = 6

The length of each side of the larger square is 6 centimeters
3 0
4 years ago
Factorize : x^2-12x-28+16y-y^2<br>​
bija089 [108]

Answer:

x=14

x=−2

Step-by-step explanation:

  Factoring  x2-12x-28

The first term is,  x2  its coefficient is  1 .

The middle term is,  -12x  its coefficient is  -12 .

The last term, "the constant", is  -28

Step-1 : Multiply the coefficient of the first term by the constant   1 • -28 = -28

Step-2 : Find two factors of  -28  whose sum equals the coefficient of the middle term, which is   -12 .

     -28    +    1    =    -27

     -14    +    2    =    -12    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -14  and  2

                    x2 - 14x + 2x - 28

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-14)

             Add up the last 2 terms, pulling out common factors :

                   2 • (x-14)

Step-5 : Add up the four terms of step 4 :

                   (x+2)  •  (x-14)

            Which is the desired factorization

6 0
3 years ago
In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who
Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0
3 years ago
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