Balloon X is filled with the carbon monoxide. Balloon Y is filled to the same volume with carbon dioxide. The balloons are left
1 answer:
Answer:
The smallest ballon is the ballon X
Explanation:
It is possible to answer this question by using Graham's law:
Where v is the speed of effusion and MW is molar weight of each compound.
This equation is showing that speed is inversely related to the square root of its molar mass. As carbon dioxide has a bigger MW than carbon monoxide, the speed of effusion of carbon dioxide is lower doing its ballon biggest than carbon monoxide ballon, thus: <em>The smallest ballon is the ballon X</em>
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<u>Answer:</u> The final equation has hydroxide ions which indicate that the reaction has occurred in a basic medium.
<u>Explanation:</u>
Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously.
The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.
A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.
The given redox reaction follows:
To balance the given redox reaction in basic medium, there are few steps to be followed:
- Writing the given oxidation and reduction half-reactions for the given equation with the correct number of electrons
Oxidation half-reaction:
Reduction half-reaction:
- Multiply each half-reaction by the correct number in order to balance charges for the two half-reactions
Oxidation half-reaction: ( × 3)
Reduction half-reaction: ( × 2)
The half-reactions now become:
Oxidation half-reaction:
Reduction half-reaction:
- Add the equations and simplify to get a balanced equation
Overall redox reaction:
As we can see that in the overall redox reaction, hydroxide ions are released in the solution. Thus, making it a basic solution
Mass of sodium thiosulfate is 110. g
Volume of the solution is 350. mL
Calculating the moles of sodium thiosulfate:
= 0.696 mol
Converting the volume of solution to L:
Finding out the concentration of solution in molarity: